Arithmetic - Profit & Loss - Previous Year CAT/MBA Questions
The best way to prepare for Arithmetic - Profit & Loss is by going through the previous year Arithmetic - Profit & Loss XAT questions. Here we bring you all previous year Arithmetic - Profit & Loss XAT questions along with detailed solutions.
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The cost of running a movie theatre is Rs. 10,000 per day, plus additional Rs. 5000 per show. The theatre has 200 seats. A new movie released on Friday. There were three shows, where the ticket price was Rs. 250 each for the first two shows and Rs. 200 for the late-night show. For all shows together, total occupancy was 80%. What was the maximum amount of profit possible?
- (a)
Rs. 1,20,000
- (b)
Rs. 87,000
- (c)
Rs. 95,000
- (d)
Rs. 91,000
- (e)
Rs. 1,16,000
Answer: Option D
Text Explanation :
There are 3 shows of 200 seats with 80% occupancy, hence 80% of 600 = 480 tickets were sold.
Profit will be maximum when maximum tickets are sold for first two shows (which have higher ticket price) and least tickets are sold for the night show (which has lower ticket price).
To maximise profit, we will assume first two shows sold 200 + 200 = 400 tickets while the late night show sold only 80 tickets
∴ Total revenue = 400 × 250 + 80 × 200 = 1,00,000 + 16,000 = 1,16,000
Also, total cost = 10000 + 3 × 5000 = 25,000
⇒ Maximum profit = 1,16,000 - 25,000 = 91,000
Hence, option (d).
Workspace:
FS food stall sells only chicken biryani. If FS fixes a selling price of Rs. 160 per plate, 300 plates of biriyani are sold. For each increase in the selling price by Rs. 10 per plate, 10 fewer plates are sold. Similarly, for each decrease in the selling price by Rs. 10 per plate, 10 more plates are sold. FS incurs a cost of Rs. 120 per plate of biriyani, and has decided that the selling price will never be less than the cost price. Moreover, due to capacity constraints, more than 400 plates cannot be produced in a day. If the selling price on any given day is the same for all the plates and can only be a multiple of Rs. 10, then what is the maximum profit that FS can achieve in a day?
- (a)
Rs. 25,300
- (b)
Rs. 28,900
- (c)
Rs. 41,400
- (d)
Rs. 52,900
- (e)
None of the remaining options is correct.
Answer: Option B
Text Explanation :
The selling price of each plate will always be a multiple of 10. So, let the number of selling price of a plate be 160 + 10x.
∴ Number of plates sold will be 300 - 10x.
Total revenue = (300 - 10x) × (160 + 10x) = -100x2 + 1400x + 48000
Total cost = 120 × (300 - 10x)
⇒ Net profit = Total revenue - Total cost
= -100x2 + 1400x + 48000 - 120 × (300 - 10x)
= -100x2 + 1400x + 48000 - 36000 + 1200x
= -100x2 + 2600x + 12000
Now, net profit is a quadratic expression -100x2 + 2600x + 12000.
This will be maximum when x = - (2600/2 × -100) = 13
∴ Maximum profit = -100 × (13)2 + 2600 × (13) + 12000
= - 16900 + 33800 + 12000
= 28,900
Hence, option (b).
Workspace:
Read the following scenario and answer the THREE questions that follow.
A store offers a choice of five different discount coupons to its customers, described as follows:
Coupon A: A flat discount of Rs. 250 on a minimum spend of Rs. 1200 in one transaction.
Coupon B: A 15% discount on a minimum spend of Rs. 500 in one transaction, up to a maximum discount of Rs. 300.
Coupon C: A flat discount of Rs. 100 on a minimum spend of Rs. 600 in one transaction.
Coupon D: A 10% discount on a minimum spend of Rs. 250 in one transaction, up to a maximum discount of Rs. 100.
Coupon E: A flat discount of Rs. 50 on a minimum spend of Rs. 200 in one transaction.
The customers are allowed to use at most one coupon in one transaction, i.e., two or more coupons cannot be combined for the same transaction.
Four customers used four different discount coupons for their respective transactions in such a way that they obtained a total discount of Rs. 710.
- (a)
Coupon A
- (b)
Coupon B
- (c)
Coupon C
- (d)
Coupon D
- (e)
Coupon E
Answer: Option E
Text Explanation :
Workspace:
Four customers used four different discount coupons for their respective transactions in such a way that nobody used any discount coupon sub-optimally. (A discount coupon is used suboptimally if using another discount coupon could have resulted in a higher discount for the same transaction.)
- (a)
Rs. 2250
- (b)
Rs. 2500
- (c)
Rs. 2350
- (d)
Rs. 2300
- (e)
Rs. 1550
Answer: Option B
Text Explanation :
Workspace:
A family wanted to purchase four products worth Rs. 1000 each, and another product worth Rs. 300.
They were told that they could:
I) pay for the five products through one or more transactions in any way they wanted, as long as the purchase amount of any one product would not get split into different transactions, and
II) use the same discount coupon repeatedly for separate transactions, if they opt for more than one transaction.
What was the maximum discount that they could obtain for their purchase?
- (a)
Rs. 600
- (b)
Rs. 645
- (c)
Rs. 650
- (d)
Rs. 700
- (e)
None of the remaining option is correct.
Answer: Option D
Text Explanation :
Workspace:
Rajnish bought an item at 25% discount on the printed price. He sold it at 10% discount on the printed price. What is his profit in percentage?
- (a)
10
- (b)
15
- (c)
17.5
- (d)
20
- (e)
None of the above
Answer: Option D
Text Explanation :
Let the printed price be Rs. 100.
Cost price for Rajnish after 25% discount = Rs. 75
Rajnish sold it at 10% discount in printed price i.e., at Rs. 90
∴ Required profit % = = = 20%
Hence, option (d).
Workspace:
Sheela purchases two varieties of apples - A and B - for a total of Rupees 2800. The weights in kg of A and B purchased by Sheela are in the ratio 5 : 8 but the cost per kg of A is 20% more than that of B. Sheela sells A and B with profits of 15% and 10% respectively. What is the overall profit in Rupees?
- (a)
340
- (b)
600
- (c)
240
- (d)
480
- (e)
380
Answer: Option A
Text Explanation :
The two types of apples sold A and B are bought in the ratio of 5: 8.
Considering the weights to be 5x and 8x.
The cost price of A is 20 percent higher than that of B.
Considering the cost price of B = y, A = 6y/5.
The total cost price of A = (5x) ∙
The total cost price of B = (8x) ∙ (y)
THe total cost price = 8xy + 6xy = 14xy
14xy = 2800.
xy = 200.
THe cost price of A = 1200.
THe cost price of B = 1600.
A is sold a profit of 15 percent. 15 percent of 1200 = 180.
B is sold at a profit of 10 percent. 10 percent of 1600 = 160.
The total profit is 180 + 160
= 340
Workspace:
An article is marked x% above the cost price. A discount of 2/3x% if given on the marked price. If the profit is 4% of the cost price and the value of x lies between 25 and 50, then the value of 50% of x is:
- (a)
15
- (b)
13
- (c)
20
- (d)
16
- (e)
12
Answer: Option A
Text Explanation :
Let the CP of the article be Rs 100.
∴ M.P = 100 + x
As a discount of 2x/3 % is given on the Marked Price.
SP = (100 + x) …(1)
Also, since profit is 4%, it means selling price = 100 + 4 = 104 …(2)
Equating (1) and (2)
⇒ (100 + x) = 104
⇒ 100 + x – – = 104
⇒ - + 4 = 0
⇒ x2 – 50x + 600 = 0
⇒ x = 20 or 30.
Since it is given that x is between 25 and 50 hence x = 30.
∴ 50% of 30 = 15.
Hence, option (a).
Workspace:
A shop, which sold same marked price shirts, announced an offer - if one buys three shirts then the fourth shirt is sold at a discounted price of ₹ 100 only. Patel took the offer. He left the shop with 20 shirts after paying ₹ 20,000. What is the marked price of a shirt?
- (a)
Rs. 1260
- (b)
Rs. 1300
- (c)
Rs. 1350
- (d)
Rs. 1400
- (e)
Rs. 1500
Answer: Option B
Text Explanation :
Let the marked price of a shirt = M
∴ If a customer buys 3 shirts then the fourth shirt would be given at a discounted price of 100 rupees.
⇒ Total cost of 4 shirts = 3M + 100
Customer bought a total of 20 shirts, hence he bought 15 shirts and marked price and got 5 shirts at the discounted price.
∴ Total amount paid by the customer = 15M + 500
⇒ 15M + 500 = 20,000
⇒ M = 1300
Hence, option (b).
Workspace:
Rani bought more apples than oranges. She sells apples at Rs. 23 apiece and makes 15% profit. She sells oranges at Rs. 10 apiece and marks 25% profit. If she gets Rs. 653 after selling all the apples and oranges, find her profit percentage.
- (a)
16.8%
- (b)
17.4%
- (c)
17.9%
- (d)
18.5%
- (e)
19.1%
Answer: Option B
Text Explanation :
Let the number of apples sold be ‘a’ and the number of oranges sold be ‘o’.
∴ Total Selling Price = 23a + 10b = 653
In R.H.S., there is a 3 in the unit’s place
∴ 23a + 10b should end with 3.
Now, unit’s digit of 10b will be ‘0’ hence units digit of 13a should be 3.
For this the values possible values of ‘a’ are 1, 11, 21, …
When a = 11, b = 40 [not possible since a should be more than b.]
When, a = 21, b = 17 which is in line with the condition of a > b
When a ≥ 31, b is negative, hence we will not consider those values.
∴ a = 21 and b = 17.
Now, the profit per apple is 15% and profit per orange is 25%
Cost price of each apple = 23/1.15 = Rs. 20
Cost price of each orange = 10/1.25 = Rs. 8
∴ Total Cost price = 20a + 8b = Rs.556
∴ Profit percent = ((653 - 556)/ 556) × 100 = 17.4%
Hence, option (b).
Workspace:
Company ABC starts an educational program in collaboration with Institute XYZ. As per the agreement, ABC and XYZ will share profit in 60 : 40 ratio. The initial investment of Rs. 100,000 on infrastructure is borne entirely by ABC whereas the running cost of Rs. 400 per student is borne by XYZ. If each student pays Rs. 2000 for the program find the minimum number of students required to make the program profitable, assuming ABC wants to recover its investment in the very first year and the program has no seat limits.
- (a)
63
- (b)
84
- (c)
105
- (d)
157
- (e)
167
Answer: Option C
Text Explanation :
Initial investment by ABC = 1,00,000
Let the total number of students be x.
Net profit from a student = 2000 – 400 = Rs. 1600
Net profit from ‘x’ students = 1600x
This will be divided between ABC and XYZ in the ratio of 60 : 40 i.e., 3 : 2.
∴ ABC will receive 1600x × 3/5
Hence, 1600x × 3/5 ≥ 1,00,000
⇒ x ≥ 104.2
∴ Minimum number of students should be 105.
Hence, option (c).
Workspace:
The Maximum Retail Price (MRP) of a product is 55% above its manufacturing cost. The product is sold through a retailer, who earns 23% profit on his purchase price. What is the profit percentage (expressed in nearest integer) for the manufacturer who sells his product to the retailer? The retailer gives 10% discount on MRP.
- (a)
31%
- (b)
22%
- (c)
15%
- (d)
13%
- (e)
11%
Answer: Option D
Text Explanation :
Let Manufacturing Cost = Rs. 100
M.R.P = Rs. 155
Discount = 10%
S.P (of retailer) = 155 ×.9 = Rs. 139.5
Profit% (of retailer) = 23%
S.P. (of manufacturer) = 139.5 × (100/123) = Rs. 113
Profit % (of manufacturer) = 13%
Hence, option (d).
Workspace:
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