CRE 1 - Basics (Functions) | Algebra - Functions & Graphs
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If f(x,y) = x2 - y3, then f(3, -2) =
Answer: 17
Workspace:
A function f is defined such that it satisfies f(x) = f(x – 1) – f(x – 2). If x is a natural number and f(1) = 0, f(0) = 1, then the value of f(5) is equal to
- (a)
0
- (b)
1
- (c)
-1
- (d)
2
Answer: Option B
Workspace:
If g is a function such that g(0) = 2, g(1) = 3 and g(x + 2) = 2g(x) – g(x + 1) then g(5) is
- (a)
13
- (b)
-3
- (c)
-1
- (d)
-2
Answer: Option A
Workspace:
A function f (x) is defined, satisfying the relation f(x + y) = f(x) × f (y) for every real value of x and y ; Given f (1) = 2 and f(1) + f(2) + f(3) + ……f(n) = 510. The value of n is
- (a)
5
- (b)
6
- (c)
7
- (d)
8
Answer: Option D
Workspace:
Given, f(1) = 1 and n × f(x) = f(nx), then f(1) + f(2) + f(3) + … + f(100) =
- (a)
5100
- (b)
4950
- (c)
5050
- (d)
None of these
Answer: Option C
Workspace:
f(x) = x(x + 1) ; x = 1,2,3, ........ Find the value of S = f(1) + f(2) + f(3) + ............. + f(10).
- (a)
438
- (b)
455
- (c)
440
- (d)
490
Answer: Option C
Workspace:
The function f(x) is defined as f(xy) = f(x) + f(y). Also, f(2) = 3 and f(3) = 2. Find the value of f(16/27).
- (a)
0
- (b)
6
- (c)
8
- (d)
None of these
Answer: Option B
Workspace:
Answer the next 3 questions based on the information given below:
lt(x, y) = Least of (x, y)
md(x) = |x|
ma(x, y) = Maximum of (x, y)
Find the value of ma(x + md(lt(x, y)), md(x + ma(md(x), md(y))), at x = -2 and y = -3.
- (a)
1
- (b)
0
- (c)
5
- (d)
3
Answer: Option A
Workspace:
Which of the following must always be correct for x, y > 0?
- (a)
md(lt(x, y)) ≥ (ma(md(x), md(y))
- (b)
md(lt(x, y)) > (ma(md(x), md(y))
- (c)
md(lt(x, y)) < (lt(md(x), md(y))
- (d)
md(lt(x,y)) = lt(md(x), md(y))
Answer: Option D
Workspace:
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