Miscellaneous - Previous Year CAT/MBA Questions

The best way to prepare for Miscellaneous is by going through the previous year Miscellaneous CAT questions. Here we bring you all previous year Miscellaneous CAT questions along with detailed solutions.

Click here for previous year questions of other topics.

It would be best if you clear your concepts before you practice previous year Miscellaneous CAT questions.

26. CAT 1998 QA | Miscellaneous CAT Question

If the storage cost is reduced to Re 0.80 per cubic feet per day, then on which day(s), should the truck be hired?

(a)
4th
(b)
7th
(c)
4th and 7th
(d)
None of these

27. CAT 1996 QA | Miscellaneous CAT Question

Find the value of $\frac{1}{1 + \frac{1}{3 - \frac{4}{2 + \frac{1}{3 - \frac{1}{2}}}}} + \frac{3}{3 - \frac{4}{3 + \frac{1}{2 - \frac{1}{2}}}}$

(a)
$\frac{13}{7}$
(b)
$\frac{15}{7}$
(c)
$\frac{11}{21}$
(d)
$\frac{17}{28}$

Answer: Option B

Text Explanation :

$\frac{1}{1 + \frac{1}{3 - \frac{4}{2 + \frac{1}{3 - \frac{1}{2}}}}} + \frac{3}{3 - \frac{4}{3 + \frac{1}{2 - \frac{1}{2}}}}$

$= \frac{1}{1 + \frac{1}{3 - \frac{4}{2 + \frac{2}{5}}}} + \frac{3}{3 - \frac{4}{3 + \frac{1}{\frac{3}{2}}}}$

$= \frac{1}{1 + \frac{1}{3 - \frac{4}{\frac{12}{5}}}} + \frac{3}{3 - \frac{4}{3 + \frac{1}{\frac{3}{2}}}}$

$= \frac{1}{1 + \frac{1}{3 - \frac{5}{3}}} + \frac{3}{3 - \frac{4}{3 + \frac{2}{3}}} = \frac{1}{1 + \frac{1}{\frac{4}{3}}} + \frac{3}{3 - \frac{4}{\frac{11}{3}}}$

$= \frac{1}{1 + \frac{3}{4}} + \frac{3}{3 - \frac{12}{11}} = \frac{1}{3 - \frac{12}{11}} + \frac{3}{3 - \frac{12}{11}} = \frac{1}{\frac{7}{4}} + \frac{3}{\frac{21}{11}}$

$= \frac{4}{7} + \frac{11}{7} = \frac{15}{7}$

28. CAT 1995 QA | Miscellaneous CAT Question

A, B, C and D are four towns, any three of which are non-collinear. Then the number of ways to construct three roads each joining a pair of towns so that the roads do not form a triangle is

(a)
7
(b)
8
(c)
9
(d)
24

29. CAT 1993 QA | Miscellaneous CAT Question

139 persons have signed up for an elimination tournament. All players are to be paired up for the first round, but because 139 is an odd number one player gets a bye, which promotes him to the second round, without actually playing in the first round. The pairing continues on the next round, with a bye to any player left over. If the schedule is planned so that a minimum number of matches is required to determine the champion, the number of matches which must be played is

(a)
136
(b)
137
(c)
138
(d)
139

30. CAT 1993 QA | Miscellaneous CAT Question

There are ten 50 paise coins placed on a table. Six of these show tails, four show heads. A coin is chosen at random and flipped over (not tossed). This operation is performed seven times. One of the coins is then covered. Of the remaining nine coins, five show tails and four show heads. The covered coin shows

(a)
a head
(b)
a tail
(c)
more likely a head
(d)
more likely a tail

The following functions have been defined for three numbers A, B and C:

@ (A, B) = average of A and B
*(A, B) = product of A and B
/(A, B) = A divided by B

Answer these questions with the above data.

31. CAT 1993 QA | Miscellaneous CAT Question

If A = 2 and B = 4, the value of @(/(*(A, B), B), A) would be

(a)
2
(b)
4
(c)
6
(d)
16

32. CAT 1993 QA | Miscellaneous CAT Question

The sum of A and B is given by

(a)
*(@(A, B), 2)
(b)
/(@(A, B), 2)
(c)
@(*(A, B), 2)
(d)
@(/(A, B), 2)

33. CAT 1993 QA | Miscellaneous CAT Question

The sum of A, B, and C is given by

(a)
*(@(*(@(B, A), 2), C), 3)
(b)
/(@(*(@(B, A), 3), C), 2)
(c)
/(*(@(*(B, A), 2), C), 3)
(d)
None of these

34. CAT 1991 QA | Miscellaneous CAT Question

A calculator has two memory buttons, A and B. Value 1 is initially stored in both memory locations.

The following sequence of steps is carried out five times:

add 1 to B
multiply A to B
store the result in A

What is the value stored in memory location A after this procedure?

(a)
120
(b)
450
(c)
720
(d)
250

	A	B	Step I (B + 1)	Step II (A × B)	Step III A	Step III B
Beginning	1	1
1^st time	1	1	B = 2	(1 × 2) = 2	2	2
2^nd time	2	2	B = 3	(2 × 3) = 6	6	3
3^rd time	6	3	B = 4	(6 × 4) = 24	24	4
4^th time	24	4	B = 5	(24 × 5) = 120	120	5
5^th time	120	5	B = 6	(120 × 6) = 720	720	6

35. CAT 1991 QA | Miscellaneous CAT Question

In a six-node network, two nodes are connected to all the other nodes. Of the remaining four, each is connected to four nodes. What is the total number of links in the network?

(a)
13
(b)
15
(c)
7
(d)
26

Previous 1 2

Miscellaneous - Previous Year CAT/MBA Questions

Feedback