Ratio, Proportion and Partnership
- Ratio, Proportion & Partnership
- CRE 1 - Ratio
- CRE 2 - Proportion
- CRE 3 - Partnership
- PE 1 - Ratio
Percentage, Profit & Loss
- Percentage
- Profit & Loss
- CRE 1 - Percentage
- CRE 2 - Percentage Change
- CRE 3 - Successive Percentage Change
- CRE 4 - Profit & Loss
- CRE 5 - Discount
- PE 1 - Percentage
Simple and Compound Interest
- Simple & Compound Interest
- CRE 1 - Simple Interest
- CRE 2 - Compound Interest
Average, Mixture & Alligation
- Average
- Mixture & Alligation
- CRE 1 - Simple Average
- CRE 2 - Numbers Added/Removed
- CRE 3 - Weighted Average
- PE 1 - Average
- PE 2 - Average
Time and Work
- Time and Work
- CRE 1 - Basics
- CRE 2 - Working in Shifts
- CRE 3 - Payments
- CRE 4 - Man Days (single group of people)
- CRE 5 - Man Days (multiple groups of people)
- CRE 6 - Pipes & Cisterns
- PE 1 - Time and Work
Time, Speed and Distance
- Time, Speed and Distance
- CRE 1 - Basics
- CRE 2 - Relative Speed
- CRE 3 - Trains
- CRE 4 - Boats & Streams
Numbers
- CRE 1 - Simplification
- PE 1 - LCM & HCF
- PE 2 - LCM & HCF
- PE 3 - Unit's Digit
Indices & Surds
- CRE 1 - Indices
- CRE 2 - Surds
Linear & Quadratic Equations
Permutations, Combinations & Probability
Geometry, Mensuration & Trigonometry
- Geometry Basics
- CRE 1 - Geometry Basics
- CRE 2 - Triangles
- CRE 3 - Circles
- CRE 4 - Mensuration
- CRE 5 - Trigonometry
Data Interpretation
- CRE 1 - Tables
Arrangements, Ranking & Ordering
- PE 1 - Arrangements
- PE 2 - Ranking
- PE 3 - Ordering
Analogy & Odd One Out
- PE 1 - Word Analogy
- PE 2 - Word Analogy
- PE 3 - Alphabet Analogy
- PE 4 - Numbers Analogy
- PE 5 - Odd One Out
Number & Alphabet Series
- PE 1 - Number Series
- PE 2 - Alphabet Series
Coding & Decoding
- PE 1 - Coding & Decoding
Clocks & Calendars
- PE 1 - Clocks
- PE 2 - Calendars
Venn Diagram
- CRE 1 - Venn Diagram
- CRE 2 - Venn Diagram
progression
Mathematical Operations
- PE 1 - Mathematical Operations
Dice & Cubes
- PE 1 - Dice
Visual Reasoning
Blood Relation & Direction Sense
- PE 1 - Blood Relation
- PE 2 - Direction Sense
General Knowledge & Current Affairs
Syllogisms

CRE 2 - Compound Interest | Simple and Compound Interest

1. CRE 2 - Compound Interest | Simple and Compound Interest

Find the C.I. on Rs. 2000 for 3 years at 10% p.a.

A.
Rs. 562
B.
Rs. 662
C.
Rs. 500
D.
Rs. 516.50

Answer: Option B

Explanation :

C.I. = Amount due – Principal

C.I. = P ${(1 + \frac{r}{100})}^{n} - P$

C.I. = $P \{{(1 + \frac{r}{100})}^{n} - 1\}$

= 2000 $\{{(1 + \frac{10}{100})}^{3} - 1\} = 662$

Hence, option (b).

2. CRE 2 - Compound Interest | Simple and Compound Interest

Find the C.I. on 5000 for 2 years at 4 1/2% p.a. when interest iscompounded annually.

A.
Rs. 460.125
B.
Rs. 480
C.
Rs. 620.14
D.
Rs. 504.5

Answer: Option A

Explanation :

C.I. =5000 $\{{(1 + \frac{\frac{9}{2}}{100})}^{2} - 1\} = 230.06$

Hence, option (a).

3. CRE 2 - Compound Interest | Simple and Compound Interest

Find the C.I. on Rs. 2000 at 12% p.a. for 3 years when the C.I. is reckoned yearly.

A.
Rs. 881.84
B.
Rs. 809.86
C.
Rs. 888.48
D.
Rs. 848.88

Answer: Option B

Explanation :

C.I. = $2000 [{(1 + \frac{12}{100})}^{3} - 1] = 202.46$

Hence, option (b).

4. CRE 2 - Compound Interest | Simple and Compound Interest

What will Rs. 12,500 amount to at C.I. for 3 years at 4% when C.I. is reckoned yearly.

A.
Rs. 13,600.2
B.
Rs. 13,801.2
C.
Rs. 14,200
D.
Rs. 14,060.80

Answer: Option D

Explanation :

$A = P {(1 + \frac{r}{100})}^{n} = 6250 {(1 + \frac{4}{100})}^{3} = 14, 060.80$

Hence, option (d).

5. CRE 2 - Compound Interest | Simple and Compound Interest

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A.
2
B.
$2 \frac{1}{2}$
C.
3
D.
4

Answer: Option A

Explanation :

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then,

$30000 {(1 + \frac{7}{100})}^{n} = 34347 {(\frac{107}{100})}^{n} = \frac{34347}{30000} = \frac{11449}{10000} = {(\frac{107}{100})}^{2}$

∴ n = 2 years.

Hence, option (a).

6. CRE 2 - Compound Interest | Simple and Compound Interest

At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?

A.
6%
B.
6.5%
C.
7%
D.
7.5%

Answer: Option A

Explanation :

Let the rate be R% p.a.

Then,

$1200 {(1 + \frac{R}{100})}^{2} = 1348.32 {(1 + \frac{R}{100})}^{2} = \frac{134832}{120000} = \frac{11236}{10000} = {(\frac{106}{100})}^{2}$

$1 + \frac{R}{100} = \frac{106}{100}$

∴ R = 6%

Hence, option (a).

7. CRE 2 - Compound Interest | Simple and Compound Interest

Every year an amount increases by 1/8th of itself, How much will it be after two years if its present value is Rs. 64000?

A.
Rs. 81000
B.
Rs. 80000
C.
Rs. 75000
D.
None of these

Answer: Option A

Explanation :

Here rate = $\frac{1}{8} \times 100 % = 12.5 A = 64000 {(1 + \frac{12.5}{100})}^{2} = 81000$

Hence, option (a).

8. CRE 2 - Compound Interest | Simple and Compound Interest

What is the compound interest on Rs. 6950 for 3 years if interest is payable half-yearly, at the rate of 6% p.a. for the first two years and at the rate of 9% p.a. for the third year

A.
Rs. 1590
B.
Rs. 1502
C.
Rs. 1482
D.
Rs. 1615

Answer: Option A

Explanation :

C.I = $6950 \{{(1 + \frac{3}{100})}^{4} {(1 + \frac{4.5}{100})}^{2}\} = 1590$

Hence, option (a).

9. CRE 2 - Compound Interest | Simple and Compound Interest

Determine the C.I. on Rs. 2400 at 10% p.a. for $1 \frac{1}{2}$ years when C.I. is compounded half yearly.

A.
Rs. 367.20
B.
Rs. 390
C.
Rs. 387.10
D.
Rs. 378.30

Answer: Option D

Explanation :

Rate of interest for half year = 10/2 = 5%

Number of compounding periods = 2 × 1.5 = 3.

C.I. = $2400 \{{(1 + \frac{5}{100})}^{3} - 1\} = 378.30$

Hence, option (d).

10. CRE 2 - Compound Interest | Simple and Compound Interest

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is:

A.
6.06%
B.
6.07%
C.
6.08%
D.
6.09%

Answer: Option D

Explanation :

Amount of Rs. 100 for 1 year when compounded half-yearly = Rs. $[100 \times {(1 + \frac{3}{100})}^{2}] = R s . 106.09$

∴ Effective rate = (106.09 - 100)% = 6.09%
.
Hence, option (d)

11. CRE 2 - Compound Interest | Simple and Compound Interest

A sum of money put out at C.I. amounts to Rs. 57,840 in 2 years and in 3 years to Rs. 61,455. Find the rate of interest.

A.
$5 \frac{3}{4} %$
B.
6%
C.
$5 \frac{1}{2} %$
D.
$6 \frac{1}{4} %$

Answer: Option D

Explanation :

In C.I., amount increases by R% every year.

∴ 61,455 – 57,840 = 3,615

Now, 3,615 is the interest on Rs. 57,840

∴ Rate $= \frac{3, 615 \times 100}{57, 840 \times 1} = 6 \frac{1}{4} %$

Hence, option (d).

12. CRE 2 - Compound Interest | Simple and Compound Interest

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:

A.
3
B.
4
C.
5
D.
6

Answer: Option B

Explanation :

$P {(1 + \frac{20}{100})}^{n} > 2 P \Rightarrow {(\frac{6}{5})}^{n} > 2$

Now, $(\frac{6}{5} \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5}) > 2$

So, n = 4 years.

Hence, option (b).

13. CRE 2 - Compound Interest | Simple and Compound Interest

Find the amount due on Rs. 2000 for 2.5 years at 10% p.a., compounded yearly.

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Answer: 2541

Explanation :

Amount due = $P {(1 + \frac{r}{100})}^{n}$

When we have incomplete years, we calculate the amount due for complete years on CI basis and then for the incomplete year we calculate amount due on SI basis.

Amount due = $2000 {(1 + \frac{10}{100})}^{2} \times (1 + \frac{10 \times \frac{1}{2}}{100}) = 2541$

Hence, 2541.

14. CRE 2 - Compound Interest | Simple and Compound Interest

A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:

A.
Rs. 120
B.
Rs. 121
C.
Rs.122
D.
Rs.123

Answer: Option B

Explanation :

Amount = $[1600 \times {(1 + \frac{5}{2 \times 100})}^{2} + 1600 \times (1 + \frac{5}{2 \times 100})] = R s . 3321$

∴ C.I. = Rs. (3321 - 3200) = Rs. 121

Hence, option (b).

15. CRE 2 - Compound Interest | Simple and Compound Interest

What is the difference between the compound interests on Rs. 5000 for 1 years at 4% per annum compounded yearly and half-yearly?

A.
Rs.2.04
B.
Rs. 3.06
C.
Rs.4.80
D.
Rs.8.30

Answer: Option A

Explanation :

C.I. when interest compounded yearly = $[5000 \times (1 + \frac{4}{100}) \times (1 + \frac{\frac{1}{2} \times 4}{100})] = (5000 \times \frac{26}{25} \times \frac{51}{50}) = 5304$

C.I. when interest is compounded half-yearly =

$[5000 \times {(1 + \frac{2}{100})}^{3}] = (5000 \times \frac{51}{50} \times \frac{51}{50} \times \frac{51}{50}) = 5306.04$

∴ Difference = Rs. (5306.04 - 5304) = Rs. 2.04

Hence, option (a).

16. CRE 2 - Compound Interest | Simple and Compound Interest

The effective annual rate of interest corresponding to a nominal rate of 12% per annum payable every 4 months is:

A.
1.78%
B.
12.49%
C.
12%
D.
13.26%

Answer: Option B

Explanation :

Amount of Rs. 100 for 1 year when compounded every 4 months = Rs

$[100 \times {(1 + \frac{\frac{12}{3}}{100})}^{3}] = R s . 112.49$

∴ Effective rate = (112.49 - 100)% = 12.49%

Hence, option (b).

17. CRE 2 - Compound Interest | Simple and Compound Interest

An amount lent at CI becomes 5 times in 7 years. How long will it take for the amount to become 125 times when lent at same rate of interest?

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18. CRE 2 - Compound Interest | Simple and Compound Interest

An amount lent at CI doubles in 2 years. How long will it take for the amount to become 8 times when lent at same rate of interest?

A.
15 years
B.
21 years
C.
6 years
D.
Can’t be determined

Answer: Option C

Explanation :

Amount due $= P {(1 + \frac{r}{100})}^{t}$

$\Rightarrow 2 P = P {(1 + \frac{r}{100})}^{2} \Rightarrow 2 = {(1 + \frac{r}{100})}^{2}$

Now, the amount has to quadruple at same rate of interest.

$\Rightarrow 8 P = P {(1 + \frac{r}{100})}^{t} \Rightarrow 8 = {(1 + \frac{r}{100})}^{t} \Rightarrow 2^{3} = {(1 + \frac{r}{100})}^{t} \Rightarrow {[{(1 + \frac{r}{100})}^{2}]}^{3} = {(1 + \frac{r}{100})}^{t} \Rightarrow {(1 + \frac{r}{100})}^{6} = {(1 + \frac{r}{100})}^{t}$

⇒ t = 6 years.

Alternately,

For CI, since amount doubles in 2 years, it means the amount will double every 2 years.

For the amount to become 8 (= 2³) times, it has to double 3 times. Hence, time required = 2 + 2 + 2 = 6 years.

Hence, option (c).

19. CRE 2 - Compound Interest | Simple and Compound Interest

Find the amount due on Rs. 1000 for 2 1/3 years at 30% p.a., compounded yearly.

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Answer: 1859

Explanation :

Amount due = $P {(1 + \frac{r}{100})}^{n}$

When we have incomplete years, we calculate the amount due for complete years on CI basis and then for the incomplete year we calculate amount due on SI basis.

Amount due = $1000 {(1 + \frac{30}{100})}^{2} \times (1 + \frac{30 \times \frac{1}{3}}{100}) = 1859$

Hence, 1859.

CRE 2 - Compound Interest | Simple and Compound Interest

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