Ratio, Proportion and Partnership
- Ratio, Proportion & Partnership
- CRE 1 - Ratio
- CRE 2 - Proportion
- CRE 3 - Partnership
- PE 1 - Ratio
Percentage, Profit & Loss
- Percentage
- Profit & Loss
- CRE 1 - Percentage
- CRE 2 - Percentage Change
- CRE 3 - Successive Percentage Change
- CRE 4 - Profit & Loss
- CRE 5 - Discount
- PE 1 - Percentage
Simple and Compound Interest
- Simple & Compound Interest
- CRE 1 - Simple Interest
- CRE 2 - Compound Interest
Average, Mixture & Alligation
- Average
- Mixture & Alligation
- CRE 1 - Simple Average
- CRE 2 - Numbers Added/Removed
- CRE 3 - Weighted Average
- PE 1 - Average
- PE 2 - Average
Time and Work
- Time and Work
- CRE 1 - Basics
- CRE 2 - Working in Shifts
- CRE 3 - Payments
- CRE 4 - Man Days (single group of people)
- CRE 5 - Man Days (multiple groups of people)
- CRE 6 - Pipes & Cisterns
- PE 1 - Time and Work
Time, Speed and Distance
- Time, Speed and Distance
- CRE 1 - Basics
- CRE 2 - Relative Speed
- CRE 3 - Trains
- CRE 4 - Boats & Streams
Numbers
- CRE 1 - Simplification
- PE 1 - LCM & HCF
- PE 2 - LCM & HCF
- PE 3 - Unit's Digit
Indices & Surds
- CRE 1 - Indices
- CRE 2 - Surds
Linear & Quadratic Equations
Permutations, Combinations & Probability
Geometry, Mensuration & Trigonometry
- Geometry Basics
- CRE 1 - Geometry Basics
- CRE 2 - Triangles
- CRE 3 - Circles
- CRE 4 - Mensuration
- CRE 5 - Trigonometry
Data Interpretation
- CRE 1 - Tables
Arrangements, Ranking & Ordering
- PE 1 - Arrangements
- PE 2 - Ranking
- PE 3 - Ordering
Analogy & Odd One Out
- PE 1 - Word Analogy
- PE 2 - Word Analogy
- PE 3 - Alphabet Analogy
- PE 4 - Numbers Analogy
- PE 5 - Odd One Out
Number & Alphabet Series
- PE 1 - Number Series
- PE 2 - Alphabet Series
Coding & Decoding
- PE 1 - Coding & Decoding
Clocks & Calendars
- PE 1 - Clocks
- PE 2 - Calendars
Venn Diagram
- CRE 1 - Venn Diagram
- CRE 2 - Venn Diagram
progression
Mathematical Operations
- PE 1 - Mathematical Operations
Dice & Cubes
- PE 1 - Dice
Visual Reasoning
Blood Relation & Direction Sense
- PE 1 - Blood Relation
- PE 2 - Direction Sense
General Knowledge & Current Affairs
Syllogisms

CRE 1 - Basics | Time, Speed and Distance

1. CRE 1 - Basics | Time, Speed and Distance

A person crosses a 1200 m long street in 20 minutes. What is his speed in km per hour?

A.
3.6
B.
7.2
C.
8.4
D.
10

Answer: Option A

Explanation :

Speed = $\frac{1200 m}{20 \times 60 s e c}$ = 1 m/sec.

Converting m/sec to km/hr = (1 × 18/5) km/hr = 3.6 kmph

Hence, option (a).

2. CRE 1 - Basics | Time, Speed and Distance

Aakash walks at 5 kmph and reaches his school, 2 km away. How long will he take (in minutes) to reach the school?

A.
24
B.
22
C.
25
D.
28

3. CRE 1 - Basics | Time, Speed and Distance

A train travels 184.8km/h. How many meters will it travel in 5 minutes?

A.
15400
B.
1540
C.
154
D.
15.40

Answer: Option A

Explanation :

Speed of train = $(184.8 \times \frac{5}{18}) = \frac{154}{3}$ m/sec.

Distance covered in (5 × 60) sec = $\frac{154}{3}$ × 5 × 60 = 15400 meters

Hence, option (a).

4. CRE 1 - Basics | Time, Speed and Distance

Aakash takes 5 sec to cover certain distance at 54 km/hr. What is the total distance covered by him in those 5 seconds (in meters)?

A.
70
B.
75
C.
60
D.
80

5. CRE 1 - Basics | Time, Speed and Distance

Aakash walks at 10 kmph from his office and reaches his home in 1 hour 12 mins. How far is his home from his office (in km)?

A.
10
B.
16
C.
15
D.
12

6. CRE 1 - Basics | Time, Speed and Distance

A man covers a certain distance in 2 hours 45 min, when he walks at the rate of 8 km/h. How much time will he take to cover the same distance if he runs at a speed of 33 km/h?

A.
40 min
B.
41 min 15 sec
C.
45 min
D.
100 min

Answer: Option A

Explanation :

2 hours 45 mins = 2 + 45/60 = 11/4 hours.

∴ Distance = Speed × time = 8 × $\frac{11}{4}$ = 22 kms.

⇒ Time taken while running at 33 kmph = $\frac{22}{33}$ hrs = $\frac{22}{33}$ × 60 mins = 40 mins

Hence, option (a).

7. CRE 1 - Basics | Time, Speed and Distance

Ankush can cover a certain distance in 21 mins. He covers two third of it at 8 km an hour and the remaining at 10 km an hour. The total distance is:

A.
2.5 km
B.
4.6 km
C.
4 km
D.
3 km

Answer: Option D

Explanation :

Let the distance be x km.

Then, total time taken = $\frac{\frac{2 x}{3}}{8} + \frac{\frac{x}{3}}{10}$

$\Rightarrow (\frac{2 x}{3} \times \frac{1}{8}) + (\frac{x}{3} \times \frac{1}{10}) = \frac{21}{60}$

⇒ x = 3 kms.

Hence, option (d).

8. CRE 1 - Basics | Time, Speed and Distance

A man goes to a place at the rate of 8 km/h. He comes back on a bicycle at 32 km/h. His average speed for the entire journey is:

A.
10 km/h
B.
12.8 km/h
C.
17 km/h
D.
20 km/h

Answer: Option B

Explanation :

Distance is same while going and coming back.

Average speed = $\frac{2 D}{\frac{D}{8} + \frac{D}{32}} = \frac{2 \times 8 \times 32}{8 + 32} = \frac{64}{5}$ km/h = 12.8 km/h

Hence, option (b).

9. CRE 1 - Basics | Time, Speed and Distance

A boy goes to school with the speed of 6 km/h. and returns with a speed of 4 km/h. If he takes 10 hours in all. The distance in kilometers between the village and the school is:

A.
24
B.
28
C.
32
D.
36

Answer: Option A

Explanation :

Let distance be d km.

Then, average speed = $\frac{2 \times 6 \times 4}{6 + 4} = \frac{2 d}{10}$

∴ d = 24 km

Hence, option (a).

10. CRE 1 - Basics | Time, Speed and Distance

A car covers four successive 60 km. stretches at speeds of 10 km/h, 20 km/h, 30 km/h and 60 km/h respectively. Its average speed over this distance is:

A.
10 km/h
B.
20 km/h
C.
30 km/h
D.
25 km/h

Answer: Option B

Explanation :

Total time taken = $(\frac{60}{10} + \frac{60}{20} + \frac{60}{30} + \frac{60}{60})$ = 12 hrs.

Avg. speed = $\frac{240}{12}$ = 20 km/h.

Hence, option (b).

11. CRE 1 - Basics | Time, Speed and Distance

A car completes a certain journey in 16 hours. It covers half the distance at 20 km/h and the rest at 30 km/h. The length of the journey in km is :

A. 350
B.
384
C.
400
D.
420

Answer: Option B

Explanation :

Let the distance travelled during each half be x km.

Then $\frac{x}{20} + \frac{x}{30} = 16$

⇒x=192

∴ Length of journey = 2 × 192 = 384 km

Hence, option (b).

Video Solution:

12. CRE 1 - Basics | Time, Speed and Distance

A Train covers a certain distance at a speed of 120 kmph in 10 hours . To cover twice the distance in $3 \frac{1}{3}$ hours, it must travel at a speed of:

A.
1440 kmph
B.
360 kmph
C.
600 kmph
D.
720 kmph

13. CRE 1 - Basics | Time, Speed and Distance

If a person walks at 28 km/hr instead of 20 km/hr, he would have walked 80 km more. The actual distance travelled by him is:

A.
200 km
B.
224 km
C.
280 km
D.
320 km

Answer: Option A

Explanation :

Let the actual distance travelled be x km.

Then, $\frac{x}{20} = \frac{x + 80}{28}$

⇒ 28x = 20x + 1600

⇒8x = 1600

⇒ x = 200 km.

Hence, option (a)

Video Solution:

14. CRE 1 - Basics | Time, Speed and Distance

Aakash travels the first 4 hours of his journey at 120 mph speed and remaining 6 hours at 50 mph speed. What is the average speed of Aakash’s travel (in mph)?

A.
75
B.
70
C.
78
D.
80

15. CRE 1 - Basics | Time, Speed and Distance

A man completes a journey in 10 hours. He travels first half of the journey at the rate of 42 km/hr and second half at the rate of 48 km/hr. Find the total journey in km.

A.
440 km
B.
448 km
C.
460 km
D.
468 km

Answer: Option B

Explanation :

Let x be the total distance travelled.

$\frac{(\frac{1}{2}) x}{42} + \frac{(\frac{1}{2}) x}{48} = 10 \Rightarrow \frac{x}{42} + \frac{x}{48} = 20$

⇒ x = 448 kms

Hence, option (b).

Video Solution:

16. CRE 1 - Basics | Time, Speed and Distance

Aakash travels with a speed of 40 kmph by bus for 2 hours and then takes an auto which travels at 60 kmph for another 2 hours. Find his average speed (in kmph) for entire journey.

A.
50
B.
55
C.
60
D.
40

Answer: Option A

Explanation :

Average speed = $\frac{t o t a l d i s \tan c e}{t o t a l t i m e} = \frac{40 \times 2 + 60 \times 2}{4} = \frac{200}{4} = 50$ kmph

Alternately,

When time is constant average speed = Arithmetic mean of speeds = (40 + 60)/2 = 50kmph

Hence, option (a).

17. CRE 1 - Basics | Time, Speed and Distance

The ratio between the speeds of two trains is 7 : 8. If the second train runs 200 km in 1 hours, then the speed of the first train is:

A.
140 km/hr
B.
15 km/hr
C.
168 km/hr
D.
175 km/hr

18. CRE 1 - Basics | Time, Speed and Distance

Siraj travelled 600 kms by air which formed (2/5) of his trip. The part, which was one third of the whole trip, he travelled by car. The rest of the journey was performed by train. The distance travelled by train was :

A.
800 km
B.
400 km
C.
240 km
D.
900 km

Answer: Option B

Explanation :

Let the total distance be x km.

Then, $\frac{2}{5} x$ = 600 ⇒ x = 1500 km

Distance covered by car $1500 \times \frac{1}{3}$ = 500 km.

∴ Distance travelled by train = [1500 – (500 + 600)] = 400 km.

Hence, option (b).

Video Solution:

19. CRE 1 - Basics | Time, Speed and Distance

Two men start together to walk to a certain destination, one at 7.5 km an hour and another at 6 km an hour. The former arrives 15 minutes before the latter. The distance is :

A.
9.5 km
B.
8 km
C.
7.5 km
D.
6 km

Answer: Option C

Explanation :

Let the distance be x km.

Then, $\frac{x}{6} - \frac{x}{7.5} = \frac{1}{4}$

⇒x=7.5 km

Hence, option (c).

Video Solution:

20. CRE 1 - Basics | Time, Speed and Distance

A train goes from a station A to another station B at a speed of 64 km/h but returns to A at a slower speed. If its average speed for the trip is 56 km/h., the return speed of the train is nearly :

A.
48 km/h
B.
50 km/h
C.
52 km/h
D.
47.4 km/h

Answer: Option B

Explanation :

Let the return speed of train be y km/h. Then,

$\frac{2 \times 64 \times y}{64 + y} = 56$

⇒ y = 49.87 ≅ 50 km/h.

Hence, option (b).

Video Solution:

CRE 1 - Basics | Time, Speed and Distance

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