CRE 4 - Profit & Loss | Percentage, Profit & Loss
By selling a TV Trolley for Rs 1800 a carpenter loses 10%. Find his cost price
- A.
Rs. 1600
- B.
Rs. 1608
- C.
Rs. 2100
- D.
None of these
Answer: Option D
Explanation :
SP = 1800 = 90% of CP = 90/100 × CP.
⇒ CP = 1800 × 100/90 = Rs. 2000.
Hence, option (d).
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SP of an article is Rs. 80 and loss is 20%. Find the cost price
- A.
Rs. 48
- B.
Rs. 12
- C.
Rs. 100
- D.
None of these
Answer: Option C
Explanation :
CP = 80 × 100/80 = 100 Rs.
Hence, option (c).
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By selling a watch for Rs 480 a man gains 20%. Find what would have been his profit or loss percent of he had sold it for Rs. 320
- A.
Profit 10%
- B.
Loss 10%
- C.
Loss 20%
- D.
None of these
Answer: Option C
Explanation :
Selling Price of a watch = Rs. 480
Profit = 20%
Hence, SP = CP(1 + P/100)
⇒ 480 = CP(1 + 20/100)
⇒ Cost Price of the watch = Rs. 400
Now, If the selling price of the watch is Rs. 320
Then, Loss % = (400 - 320) × 100/400
⇒ Loss % = 20%
Hence, option (c).
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By selling oranges for 10 a Rs a man loses 10%. How many for a Rs. he should sell the oranges to gain 80%?
- A.
9
- B.
7
- C.
12
- D.
None of these
Answer: Option D
Explanation :
Selling price of 1 orange = Rs. 1/10
Loss % = 10%
Now, SP = CP(1 - L/100)
⇒ 1/10 = CP(1 - 10/100)
Therefore, Cost Price of 1 orange = Rs. 1/9
Now, if he had to gain 80% then,
SP = 1/9(1 + 80/100)
⇒ SP = 1/9 × 18/10
⇒ SP = Rs. 1/5
Hence, he should sell 5 oranges for a Rs. to gain 80%.
Hence, option (d).
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A fruit seller buys some mangoes at a rate of 20 for Rs. 3 and sells them at rate of 25 for Rs 4. Find his gain or loss%
- A.
6.66% profit
- B.
1% loss
- C.
1.23% loss
- D.
None of these
Answer: Option A
Explanation :
Let number of mangoes = 100
CP of 20 = 3 Rs.
∴ CP of 100 = 15 Rs
SP of 25 = 4 Rs
∴ SP of 100 = 16 Rs
∴ Profit =1/15 × 100 = 6.66%
Hence, option (a).
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Two articles are sold at Rs. 1000 each. One at a profit of 30%, while other at a loss of 30%. Find real profit or loss%.
- A.
9% gain
- B.
9% loss
- C.
No profit no loss
- D.
None of these
Answer: Option B
Explanation :
Net percentage change = 30 - 30 - (30 × 30)/100
⇒ Net change = -302/100
⇒ There is a real loss of 9%.
Option B is the correct answer.
Hence, option (b).
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A man bought 2 oranges for Rs. 5 and sells at a rate of 3 for Rs. 7. His real loss % is
- A.
- B.
- C.
- D.
None of these
Answer: Option A
Explanation :
Let no. of orange = 6
CP of 2 = 5
∴ CP of 6 = 15
SP of 3 = 7
SP of 6 = 14
∴ Loss% = 1/15 × 100 =
Hence, option (a).
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If selling price of 8 articles is equal to cost price of 10 articles. Find real profit or loss
- A.
20% profit
- B.
25% profit
- C.
30% profit
- D.
None of these
Answer: Option B
Explanation :
SP of 8 = CP of 10 = CP of 8 + CP of 2
∴ Profit% =2/8 × 100 = 25%
Hence, option (b).
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If selling price of 10 articles is equal to cost price of 8 articles. Find real profit or loss%
- A.
10% loss
- B.
20% loss
- C.
30% loss
- D.
None of these
Answer: Option B
Explanation :
SP of 10 = CP of 8 = CP of 10 – CP of 2
∴ loss % = 2/10 × 100 = 20%
Hence, option (b).
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By selling 45m of cloth a merchant gains the cost price of 15m. Find his real profit or loss%
- A.
20% profit
- B.
40% profit
- C.
33.33% profit
- D.
None of these
Answer: Option C
Explanation :
SP of 45m - CP of 45m = CP of 15m
⇒ SP of 45m = CP of 45m + CP of 15m
⇒ Gain % = 15 × 100/45
Therefore, profit % = 33.33%
Hence, option C is the correct answer.
Hence, option (c).
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By selling 33m of a merchant gains the selling price of 11m. Find his real profit or loss%
- A.
20% profit
- B.
50% profit
- C.
60% profit
- D.
None of these
Answer: Option B
Explanation :
Selling Price = Cost Price + Profit
SP of 33 = CP of 33 + SP of 11
SP of 22 = CP of 33
∴ Profit% = 11/22 × 100 = 50%
Hence, option B is the correct answer.
Hence, option (b).
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A man sold a watch for Rs 75 and got a profit percentage equals to cost price. Find Cost Price of the watch.
- A.
Rs. 50
- B.
Rs. 60
- C.
Rs. 90
- D.
None of these
Answer: Option A
Explanation :
Let the cost price be Rs. x
Hence, P% = x%
SP = CP(1 + P/100)
⇒ 75 = x(1 + x/100)
⇒ x = 50
Hence, cost price of the watch is Rs. 50
Hence, option (a).
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A man bought goods for Rs. 800 and sold half at a gain of 5%. Find at what % gain, he must sell the remaining so as to gain 20% on the whole?
- A.
25%
- B.
30%
- C.
40%
- D.
None of these
Answer: Option D
Explanation :
SP of 1st half = 400 × 105/100 = Rs. 420
SP of whole = 800 × 120/100 = Rs. 960
Therefore, Second half he should sell at = (540 – 400) × 100/400 = 140 × 100/400 = 35% profit.
Hence, option (d).
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A man buys milk at Rs. 2.40/litre. He adds one third water to it and sells the mixture at RS. 2.88/litre. Find his gain%?
- A.
50%
- B.
40%
- C.
35%
- D.
60%
Answer: Option D
Explanation :
Recognize, for every 3 litre of milk purchased, 4 litres of mixture is sold.
CP for 3 litres milk = 3 × Rs. 2.40 = Rs. 7.20
SP for 4 litres mixture = 4 × Rs. 2.88 = Rs. 11.52
∴ Profit% = (11.52 - 7.20)/7.20 = 0.6 = 60%
Hence, option (d).
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A buys an article and sells it to B at a profit of 10%, B sells it to C gaining 20%. If C gives Rs. 924, what did A give?
- A.
Rs. 725
- B.
Rs. 700
- C.
Rs. 650
- D.
Rs. 750
Answer: Option B
Explanation :
Let cost price of A be (CP)A, of B be (CP)B and that of C be (CP)C.
Similarly, selling prices be designed as (SP)A ; (SP)B and (SP)C
If (CP)A = x
Then, (CP)B = (SP)A = 1.1 x
(CP)C = (SP)B = (1.2) (1.1) x = Rs. 924 ⇒ x = Rs. 700
Hence, option (b).
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A shopkeeper sold an article at a gain of 25%. If he had paid Rs. 1.75 less for it and sold it at the same price he would have made a gain of 60%. Find the cost price?
- A.
Rs. 17.50
- B.
Rs. 9.25
- C.
Rs. 12.50
- D.
Rs. 8
Answer: Option D
Explanation :
Let CP = Rs. x and SP = Rs. 1.25 x
But it is given that, = 0.6
⇒ 0.25 x + 1.75 = 0.6 x – 1.05
⇒ x = Rs. 8
Hence, option (d).
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A boy buys eggs at 18 for Rs. 16 and sells them at 22 for Rs. 20. Find his gain or loss percent?
- A.
- B.
- C.
- D.
Answer: Option B
Explanation :
CP : 18 eggs for Rs. 16
⇒ 1 egg for Rs. 16/18
SP : 22 egg for Rs. 20
⇒ 1 egg for Rs. 20/22
=
=
= = =
Hence, option (b).
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I bought two buffaloes for Rs. 1200 and sold one to lose 5% and the other to gain 7% and on the whole I neither lost nor gained. What did each cost?
- A.
Rs. 400, Rs. 800
- B.
Rs. 600, Rs. 600
- C.
Rs. 700, Rs. 500
- D.
Rs. 900, Rs. 300
Answer: Option C
Explanation :
Let the CP’s of buffaloes be Rs. x and (1200 – x).
Then, it is given that 0.95 x + 1.07 (1200 – x) = 1200
⇒ 0.12x = 84
⇒ x = 700
∴ Cost of other buffalo = Rs. 500
Hence, option (c).
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A man buys apples at a certain price per dozen and sells them at eight times per hundred. What does he Gain or Loss %?
- A.
4% loss
- B.
4% gain
- C.
% loss
- D.
% gain
Answer: Option A
Explanation :
Easiest way to solve such problems is to assume some simple values
Let 120 apples be purchased at Rs. 12/dozen
Thus, total cost of purchase = Rs. 12 × 10 dozen = Rs. 120
Now, SP = Rs. 96 apples/100
⇒ 96/100 × 120 = SP for 120 apples = Rs. 115.20
∴ Loss% = 4.8/120 × 100 = 4%
Hence, option (a).
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Arun sold an article to Babu at a profit of 10%. Babu sold it to Chander for Rs. 60.50 and also gained 10%. What did Arun pay for it?
- A.
Rs. 45.45
- B.
Rs. 55.00
- C.
Rs. 50.0
- D.
Rs. 56.50
Answer: Option C
Explanation :
Let the (CP)Arun = x
Then, (SP)Arun = (CP)Babu = 1.1 x
(SP)Babu = (CP)Chander = Rs. 60.5 = (1.1) (1.1)x
⇒ x = 60.5/1.12 = Rs. 50
Hence, option (c).
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The manufacturer of a machine sells it to a wholesaler at a profit of 20%. The wholesaler, in turn, sells it to a retailer at a gain of 10%. The retailer sells it to a customer for Rs. 1452 at a gain of 10%. The cost price of the machine for the manufacturer is:
- A.
Rs. 870
- B.
Rs. 1000
- C.
Rs. 1050
- D.
Rs. 1200
Answer: Option B
Explanation :
Let the manufacturers cost price be m. Then,
(SP)manufacturer = (CP)wholesaler = 1.2 m
(SP)wholesaler = (CP)retailer = (1.1) (1.2) m
(CP)retailer = (CP)customer = (1.1) (1.1) (1.2) m = Rs. 1452
⇒ 1.452m = 1452
m = 1452/1.452 = 1000
Hence, option (b).
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A manufacturer sells goods to a dealer at 10% profit and the dealer to his customer at 12.5% profit. How much does a customer pay above the original cost of goods purchased by him for Rs. 990?
- A.
Rs. 150
- B.
Rs. 175
- C.
Rs. 190
- D.
Rs. 210
Answer: Option C
Explanation :
Let Manufacturer’s price be M. Then,
(SP)manufacturer = (CP)dealer = 1.1 m
(SP)dealer = (CP)customer = (1.125) (1.1) m
i.e. (1.125) (1.1) m = 990 ⇒ m = 800
∴ customer paid Rs. (990 – 800) = Rs. 190 above the manufacturer’s prize.
Hence, option (c).
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A person sold 480 meters of cloth for Rs. 225 gaining thereby the cost of 72 meters. Find his gain percent?
- A.
20%
- B.
18%
- C.
15%
- D.
12%
Answer: Option C
Explanation :
Compute selling price of 1 m cloth = Rs. 225/480 = Rs. 15/32
Let CP of 1 m cloth be x. Hence, CP of 480 m = 480 x
Then gain = 72x
gain % = (72x)/(480x) × 100 = 15%
Hence, option (c).
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Mohan sells 2 cars for Rs. 20000 each, neither gaining nor losing in the deal. If he sells one car at a loss of 20%, then the other car must have sold at a gain of
- A.
32%
- B.
23.5%
- C.
25%
- D.
33.33%
- E.
None of these
Answer: Option D
Explanation :
Cost price of the car sold at 20% loss = 100 × SP/80 =100 × 20000/80 = 25000.
Now he has incurred a loss of Rs. 5000 on this.
Now as on the whole there is "no" net loss hence he must have gained Rs. 5000 in the second.
Selling price of the second product = 20000. Profit = Rs. 5000.
So Cost Price of the second product = 20000 - 5000 = 15000.
Percentage Profit = 100 × 5000 / 15000 = 33.33%.
Hence, option (d).
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Two houses were sold for Rs. 130000 each, one at a loss of 30% and the other at a gain of 30%. The entire transaction resulted in
- A.
no loss, no gain
- B.
loss of 10%
- C.
gain of 12%
- D.
gain of 20%
- E.
None of these
Answer: Option E
Explanation :
Since the two houses are sold for 130000 each, Now use P + Q + PQ/100
We get 30 – 30 + (-30 × 30)/100 = -9%. So there will be a loss of 9%.
Hence, option (e).
Video Solution:
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