PE 1 - Time and Work | Time and Work
Some staff promised to do a job in 18 days, but 6 of them went on leave. So, the remaining men took 20 days to complete the job. How many men were there originally?
- A.
55
- B.
62
- C.
56
- D.
60
Answer: Option D
Explanation :
Let the number of staff that were supposed to come = x
∴ x men were supposed to complete the work in 18 days
Whereas, (x – 6) men completed the same work in 20 days.
⇒ x × 18 = (x – 6) × 20
⇒ 18x = 20x – 120
⇒ 120 = 2x
⇒ x = 60
Hence, option (d).
Workspace:
5 men and 5 women earn Rs. 660 in 3 days. 10 men and 20 women earn Rs. 3500 in 5 days. In how many days can 6 men and 4 women earn Rs. 1060?
- A.
5 days
- B.
10 days
- C.
6 days
- D.
12 days
Answer: Option A
Explanation :
Let the earnings of a man and a woman be m and q per day respectively.
5 men and 5 women in 3 days earn Rs. 660
∴ 5 men and 5 women in 1 day earn Rs. 220
⇒ 5m + 5w = 220 …(1)
10 men and 20 women in 5 days earn Rs. 3500
∴ 10 men and 20 women in 1 day earn Rs. 700
⇒ 10m + 20w = 700 …(2)
Solving (1) and (2), we get
m = Rs. 18 and w = Rs. 26.
∴ 6 men and 4 women in 1 day earn = 6m + 4w = 6 × 18 + 4 × 26 = Rs. 212
⇒ To earn Rs. 1060 they will take = 1060/212 = 5 days.
Hence, option (a).
Workspace:
A track of 100 m can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a track of 600 m?
- A.
15
- B.
20
- C.
25
- D.
30
Answer: Option A
Explanation :
Let efficiency of each man and woman be m and w units/day.
Given, 7m × 10 = 10w × 10
⇒ 7m = 10w
Now,
⇒
⇒
⇒ 7m × 10 × 6 = 28m × d
⇒ d = 15 days
Hence, option (a).
Workspace:
A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone would do the work in
- A.
5 days
- B.
6 days
- C.
9 days
- D.
10 days
Answer: Option B
Explanation :
Let the time taken by A and B alone be ‘A’ and ‘B’ days respectively.
Together they can complete the work in 3 days.
⇒ …(1)
Now, they work for 2 days together and rest of the work is completed by A alone in 2 more day.
⇒ 1 = × 2 + × 2
⇒ 1 = × 2+ × 2
⇒ =
⇒ A = 3 days
Substituting this in (1), we get
B = 6 days.
Hence, option (b).
Workspace:
P can complete 1/4th of a work in 10 days, Q can complete 40% of the same work in 15 days, R can complete 1/3rd of the work in 13 days and S can complete 1/6th of the work in 7 days, Who will be able to complete the work first?
- A.
P
- B.
Q
- C.
R
- D.
S
Answer: Option B
Explanation :
P can complete 1/4th of a work in 10 days.
∴ P can complete the entire work in 4 × 10 = 40 days.
Q can complete 40% i.e., 2/5th of the same work in 15 days.
∴ Q can complete the entire work in 15 × 5/2 = 37.5 days.
R can complete 1/3rd of the work in 13 days.
∴ R can complete the entire work in 13 × 3 = 39 days.
S can complete 1/6th of the work in 7 days.
∴ S can complete the entire work in 7 × 6 = 42 days.
⇒ Q completes the work first.
Hence, option (b).
Workspace:
A can do a work in 20 days and B in 40 days. If they work on it together for 5 days. Then fraction of the work that is left, is:
- A.
5/8
- B.
1/3
- C.
7/15
- D.
1/10
Answer: Option A
Explanation :
Fraction of work done in 5 days = × 5 = × 5 = th.
∴ Fraction of work left = 1 – =
Hence, option (a).
Workspace:
A is 50% as efficient as B. C does half of the work done by A and B together in same time. If C alone does the work in 20 days, then A, B and C together can do work in:
- A.
days
- B.
days
- C.
6 days
- D.
7 days
Answer: Option B
Explanation :
C’s efficiency = 1/20
C’s efficiency is half that of A and B combined.
⇒ A’s efficiency + B’s efficiency = 1/10
A is 50% as efficient as B or B’s efficiency is twice that of A.
⇒ A’s efficiency + 2 × A’s efficiency = 1/10
⇒ A’s efficiency = 1/30
⇒ Time taken by A alone to complete the work = 30 days.
∴ Time taken by B alone to complete the work = 15 days.
Now, let Time taken by A, B and C together = N days
⇒ = = = =
⇒ N = 20/3 = days.
Hence, option (b).
Workspace:
If 12 men or 18 women can make a wall in 14 days, then working at the same rate, 8 men and 16 women can make the same wall in:
- A.
9 days
- B.
5 days
- C.
7 days
- D.
8 days
Answer: Option A
Explanation :
Let the efficiency of a man and a woman be m and w units/day respectively.
∴ Work done = 12m × 14 = 18w × 14 = (8m + 16w) × d
⇒ 12m × 14 = 18w × 14
⇒ 2m = 3w
Now, 18w × 14 = (8m + 16w) × d
⇒ 18w × 14 = (12w + 16w) × d
⇒ 18w × 14 = 28w × d
⇒ d = 9 days
Hence, option (a).
Workspace:
A certain number of men complete a work in 160 days. If there were 18 men more, the work could be finished in 20 days less. How many men were originally there?
- A.
116
- B.
122
- C.
124
- D.
126
Answer: Option D
Explanation :
Let x men can complete the work in 160 days, whereas
(x + 18) men can complete the work in 140 days.
⇒ x × 160 = (x + 18) × 140
⇒ 8x = 7(x + 18)
⇒ x = 7 × 18 = 126
Hence, option (d).
Workspace:
A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?
- A.
1 day
- B.
2 days
- C.
3 days
- D.
4 days
Answer: Option A
Explanation :
Suppose the original work would have been completed in d days.
Total work to be done = 30 × d
Work done in first 25 days = 30 × 25
Work done in next 12 days = 35 × 12
⇒ 30d = 30 × 25 + 35 × 12
⇒ 30d = 750 + 420
⇒ 30d = 1170
⇒ d = 39
∴ Had 5 more men not been employed the work would have got delayed by (39 – 38 =) 1 day.
Hence, option (a).
Workspace:
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