IIFT 2009 LRDI | Previous Year IIFT Paper

Answer: Option D

Explanation :

Total Automobile Production is as follows:

Year 2004: 800 + 500 + 475 = 1775

Year 2005: 700 + 550 + 450 = 1700

Year 2006: 1025 + 675 + 475 = 2175

Year 2007: 1200 + 650 + 475 = 2325

Year 2008: 1250 + 600 + 350 = 2200

2005 and 2008 show a decrease in automobile production.

Percentage decrease for 2005 = $\frac{1775-1700}{1775}$ × 100 = 4.23%

Percentage decrease for 2008 = $\frac{2325-2200}{2325}$ × 100 = 5.38%

Hence, option (d).

Answer: Option B

Explanation :

From the previous solution, we have total Automobile Production for the given years as follows:
2004: 1775;
2005: 1700;

2006: 2175
2007: 2325
2008: 2200

Now, domestic sales can be calculated as:

Year 2004: 700 + 450 + 300 = 1450

Year 2005: 675 + 500 + 350 = 1525

Year 2006: 900 + 625 + 400 = 1925

Year 2007: 1050 + 600 + 375 = 2025

Year 2008: 975 + 550 + 350 = 1875

Exports = Total Production – Domestic sales

∴ Exports for the given years:

2004 = 1775 – 1450 = 325

2005 = 1700 – 1525 = 175

2006 = 2175 – 1925 = 250

2007 = 2325 – 2025 = 300

2008 = 2200 – 1875 = 325

∴ Highest growth in exports was registered in the year 2006 = (250 – 175) = 75

Hence, option (b).

Answer: Option A

Explanation :

Total domestic sale for the year 2004-2008:

Commercial vehicles: 450 + 500 + 625 + 600 + 550 = 2725

Passenger vehicles: 700 + 675 + 900 + 1050 + 975 = 4300

Three wheelers: 300 + 350 + 400 + 375 + 350 = 1775

∴ Ratio of the total sale price of commercial vehicles, passenger vehicles and three wheelers = (5 × 2725) : (3 × 4300) : (2 × 1775)

∴ Contribution of commercial vehicles to the overall earnings

= $\frac{(5\times 2725)}{(5\times 2725)+(3\times 4300)+(2\times 1775)}$ × 100 ≈ 45%

Hence, option (a).

Answer: Option D

Explanation :

Average domestic sales of automobiles:
(1450 + 1525 + 1925 + 2025 + 1875) ÷ 5 = 1760

The domestic sales in the year 2008 were closest to the average domestic sales.

Hence, option (d).

Answer: Option B

Explanation :

From the solution of question 2, we have the sales as follows:

Year 2004 = 1450

Year 2005 = 1525

Year 2006 = 1925

Year 2007 = 2025

Year 2008 = 1875

Subtracting the sales from the previous years, we get increase in the sales for:

Year 2005 = 75;

Year 2006 = 400;

Year 2007 = 100;

Year 2008 shows a decrease.

2006 shows the highest increase, i.e. its percentage increase in the highest.

Hence, option (b).

Answer: Option B

Explanation :

From the previous solutions;
Increase in domestic sales over the preceding year:
Year 2005 = 75;
Year 2006 = 400;
Year 2007 = 100

Increase in production over the preceding year:
Year 2006 = 475;
Year 2007 = 150

Ratio for the year 2006 = 400 : 475 = 16 : 19
Ratio for the year 2007 = 100 : 150 = 2 : 3

Hence, option (b).

Answer: Option A

Explanation :

Returns for Alpha
= (1.49 × 1.05) + (3.01 × 1.12) + (7.01 × 0.95) + (1.51 × 1.15) + (7.48 × 1.11) + (9.99 × 1.21) + (9.01 × 1.08) + (25.98 × 1.06) + (14.5 × 1.25) + (5.98 × 1.18) + (4.5 × 1.1) + (5.51 × 0.98) + (4.03 × 1.17)
= 111.2383
Similarly, returns for Beta = 107.2281
and for Gama = 109.4837
Hence, option (a).

Answer: Option D

Explanation :

Preparing a table to show the ranks:

​​​​​​​

From the table, we can conclude that only statement III is correct.

Hence, option (d).

Answer: Option B

Explanation :

Returns for Rs. 100 lakhs = Rs. 109.4837
∴ Returns for Rs. 10 lakhs ≈ Rs. 10.95 lakhs.
Hence, option (b).

Answer: Option C

Explanation :

Jowar yield (2007) = 368/673

Soyabean yield (2008) = 799/650

Ratio = $\frac{368}{673}$ : $\frac{799}{650}$ ≈ 0.445

From the given options,

1.00 : 2.10 ≈ 0.476

1.21 : 1.89 ≈ 0.64

0.89 : 2.00 = 0.445

0.78 : 1.61 ≈ 0.484

Hence, option (c).

Answer: Option B

Explanation :

Let us calculate the yield for the crops given in the options for the year 2006:
Castor Seed = 135/106 ≈ 1.27
Groundnut = 491/317 ≈ 1.55
Maize = 1102/1004 ≈ 1.1
Sunflower = 880/472 ≈ 1.86
Rice = 153/107 ≈ 1.43
Bajra = 2172/4992 ≈ 0.43
The top three crops by yield are Sunflower, Groundnut and Rice.
Hence, option (b).

Answer: Option A

Explanation :

Let us calculate the yield for the crops given in the options for the year 2008:
Moth = 250/1199 ≈ 0.21
Sesamum = 70/280 ≈ 0.25
Millets = 4/15 ≈ 0.27
Moong = 260/725 ≈ 0.36
Arhar = 9/19 ≈ 0.47
Urd = 35/102 ≈ 0.34
Chaula = 30/101 ≈ 0.30
The bottom three crops by yield are Moth, Sesamum and Millets.
Hence, option (a).

Answer: Option C

Explanation :

Total productivity has increased for some pulses and decreased for some.
∴ Statement I is incorrect.
Statements II and III are correct.
Hence, option (c).

Answer: Option A

Explanation :

On observing the table we see that,

The area under production of Cereals is approximately the same for the years 2006, 2007 and 2008 but the total quantity of production has increased.

∴ Over the period total cereal productivity has gone up.

∴ Statement I is correct.

Similarly on observing the table we can say that statement III is also correct.

Only statements I and III are correct.
Hence, option (a).

Answer: Option B

Explanation :

Total Oil Used = House Hold + Transport + Industrial + Suburban

Total Oil Produced = Total Oil Used + Oil Production Loss

​​​​​​​

Now, Oil used for House Hold as a percentage of Total Oil Used:

During 1998 = $\frac{22}{2870}$ × 100 ≈ 0.77%

During 1999 = $\frac{22}{2834}$ × 100 ≈ 0.78%

During 2000 = $\frac{20}{2920}$ × 100 ≈ 0.68%

During 2001 = $\frac{22}{3262}$ × 100 ≈ 0.67%

It is highest during the year 1999.

Hence, option (b).

Answer: Option A

Explanation :

Using the table given in the previous solution, we can find the ‘Oil Production loss’ as a proportion of ‘Total Oil Produced’

During 2002 = 386/4044 ≈ 0.095

During 2003 = 444/3944 ≈ 0.113

During 2004 = 506/4328 ≈ 0.117

During 2006 = 1142/4968 ≈ 0.230

Hence, option (a).

Answer: Option D

Explanation :

Again using the table given in the solution of the first question of the set,

During 2005 = 230/3618 ≈ 0.0636

During 2006 = 210/3826 ≈ 0.055

During 2007 = 254/4030 ≈ 0.063

During 2008 = 266/4152.2 ≈ 0.064

Hence, option (d).

Answer: Option D

Explanation :

Refer to the table given in solution 15.
Growth rate for ‘Production of Oil’:

Year 1997: (388/3258) × 100 = 11.91%

Year 1998: (58/3646) × 100 = 1.59%

Year 1999: (232/3704) × 100 = 6.26%

Year 2000: −(314/3936) × 100 = −7.98%

Year 2001: (132/3622) × 100 = 3.64%

Year 2002: (290/3754) × 100 = 7.73%

Year 2003: −(100/4044) × 100 = −2.47%

Year 2004: (384/3944) × 100 = 9.74%

Year 2005: (322/4328) × 100 = 7.44%

Year 2006: (318/4650) × 100 = 6.84%

Year 2007: (516/4968) × 100 = 10.39%

Year 2008: (96.2/5484) × 100 = 1.75%

Growth rate for ‘Total Oil Used’:

Year 1997: (306/2608) × 100 = 11.73%

Year 1998: −(44/2914) × 100 = −1.51%

Year 1999: −(36/2870) × 100 = −1.25%

Year 2000: (86/2834) × 100 = 3.03%

Year 2001: (342/2920) × 100 = 11.71%

Year 2002: (396/3262) × 100 = 12.14%

Year 2003: −(158/3658) × 100 = −4.32%

Year 2004: (322/3500) × 100 = 9.2%

Year 2005: −(204/3822) × 100 = −5.34

Year 2006: (208/3618) × 100 = 5.75%

Year 2007: (204/3826) × 100 = 5.33%

Year 2008: (122.2/4030) × 100 = 3.03%

The growth rate in ‘Production of Oil’ is more than that in ‘Total Oil Used’ during the years 1997, 1998, 1999, 2003, 2004, 2005, 2006 and 2007.

Hence, option (d).

Note:

The growth rate in 'Production of Oil' is more than that in 'Total Oil Used' for 8 years which was not there in the options in the paper. The 4th option in the paper was 6 years which has been changed here to 8 years.

Answer: Option D

Explanation :

Total Oil Used = House Hold + Transport + Industrial + Suburban

Total Oil Produced = Total Oil Used + Oil Production Loss

​​​​​​​

Now, Oil used for House Hold as a percentage of Total Oil Used:

During 1998 = $\frac{22}{2870}$ × 100 ≈ 0.77%

During 1999 = $\frac{22}{2834}$ × 100 ≈ 0.78%

During 2000 = $\frac{20}{2920}$ × 100 ≈ 0.68%

During 2001 = $\frac{22}{3262}$ × 100 ≈ 0.67%

On observing the data given in the question and the table of the set, we can conclude that the correct statement is 4.
Hence, option (d).

Answer: Option B

Explanation :

It is given that the four houses Blue, Green, Red and Yellow are located in a row, From (VIII) we get that the house in which Krishna lives is located between houses with persons earning salaries of Rs. 30,000 and Rs. 50,000.

∴ Two cases are possible:

Case 1: Krishna lives in the Green house.

​​​​​​​

Case 2: Krishna lives in the Red house.

​​​​​​​

Consider case 1: Krishna lives in the Green house.

From (I) we get that Paul lives between Som and Krishna.

∴ Som lives in the Yellow house and Paul lives in the Red house.

∴ Laxman lives in the Blue house.

From (VIII) we get that Krishna lives in the house which is located between houses with persons earning salaries of Rs. 30,000 and Rs. 50,000.

And from (III) we get that the person living in the Red house earns more than the person living in the Blue house.

∴ Paul earns Rs. 50,000 and Laxman earns Rs. 30,000.

From (VII) we get that the salary difference between Laxman and Som is Rs. 30,000 which is not possible in this case as the four given salaries are Rs. 30,000, Rs. 50,000, Rs. 80,000 and Rs. 1,10,000.

∴ Case 1 is not possible.

Consider case 2: Krishna lives in the Red house.

From (I) we get that Paul lives between Som and Krishna.

∴ Som lives in the Blue house and Paul lives in the Green house.

∴ Laxman lives in the Yellow house.

In condition (VIII) it is given that Krishna lives in the house located between houses with persons earning Rs. 30,000 and Rs. 50,000.

And from (IX) we get that the person living in the Yellow house is not earning lowest salary among the four persons.

∴ Laxman earns Rs. 50,000 and Paul earns Rs. 30,000.

From (III) we get that the person living in the Red house earns more than the person living in the Blue house.

∴ Krishna earns Rs. 1,10,000 and Som earns Rs. 80,000.

​​​​​​​

This case satisfies all the given conditions.

∴ Krishna lives in the Red house.

Hence, option (b).

Answer: Option C

Explanation :

It is given that the four houses Blue, Green, Red and Yellow are located in a row, From (VIII) we get that the house in which Krishna lives is located between houses with persons earning salaries of Rs. 30,000 and Rs. 50,000.

∴ Two cases are possible:

Case 1: Krishna lives in the Green house.

​​​​​​​

Case 2: Krishna lives in the Red house.

​​​​​​​

Consider case 1: Krishna lives in the Green house.

From (I) we get that Paul lives between Som and Krishna.

∴ Som lives in the Yellow house and Paul lives in the Red house.

∴ Laxman lives in the Blue house.

From (VIII) we get that Krishna lives in the house which is located between houses with persons earning salaries of Rs. 30,000 and Rs. 50,000.

And from (III) we get that the person living in the Red house earns more than the person living in the Blue house.

∴ Paul earns Rs. 50,000 and Laxman earns Rs. 30,000.

From (VII) we get that the salary difference between Laxman and Som is Rs. 30,000 which is not possible in this case as the four given salaries are Rs. 30,000, Rs. 50,000, Rs. 80,000 and Rs. 1,10,000.

∴ Case 1 is not possible.

Consider case 2: Krishna lives in the Red house.

From (I) we get that Paul lives between Som and Krishna.

∴ Som lives in the Blue house and Paul lives in the Green house.

∴ Laxman lives in the Yellow house.

In condition (VIII) it is given that Krishna lives in the house located between houses with persons earning Rs. 30,000 and Rs. 50,000.

And from (IX) we get that the person living in the Yellow house is not earning lowest salary among the four persons.

∴ Laxman earns Rs. 50,000 and Paul earns Rs. 30,000.

From (III) we get that the person living in the Red house earns more than the person living in the Blue house.

∴ Krishna earns Rs. 1,10,000 and Som earns Rs. 80,000.

​​​​​​​

From the final table in the solution of the set we get that,

The person earning highest salary i.e Rs. 1,10,000 is Krishna and he lives in the Red house.

Hence, option (c).

Answer: Option A

Explanation :

The person living in the Green house is Paul and the salary earned by him is Rs. 30,000.

Hence, option (a).

Answer: Option C

Explanation :

From the directions given in the questions following diagram can be drawn:

​​​​​​​

The distance between the Starting point and the final position of Mr. Raghav can be determined using Pythagoras theorem with the two sides as 12 and 5.

∴ Mr. Raghav is 13 kms to the North east of the starting point.

Hence, option (c).

Answer: Option A

Explanation :

It is given that Mr. Raju’s father’s mother, mother’s father and their children were in one car.

∴ His paternal grandmother, maternal grandfather, Mother and Father were in the first car.

Mr. Raju’s father’s son, sister’s husband and brother’s wife were in the second car.

Raju’s father’s son has to be his brother as Raju himself was in the third car.

∴ Raju’s brother, Brother-in-law (sister’s husband) and sister-in-law (brother’s wife) were in the second car.

Mr. Raju, his wife, wife’s sister, wife’s brother, son’s wife with a kid were in the third car.

∴ Mr. Raju, his wife, sister-in-law (wife’s sister), brother-in-law (wife’s brother), son’s wife and grandson were in the third car.

∴ Car 1: Paternal Grandmother, Maternal Grandfather, Mother and Father.

Car 2: Brother, Sister-in-law (brother’s wife) and Brother-in-law (sister’s husband).

Car 3: Raju, his wife, Sister-in-law (wife’s sister), Brother-in-law (wife’s brother), Son’s wife and Grandson.

∴ 13 members of Raju’s family were there in the picnic and 4 members i.e. Raju’s Sister, his wife’s brother-in-law, his wife’s sister-in-law and his son were left behind.

Hence, option (a).

Answer: Option A

Explanation :

Data given in the question is not correct.

Let a, b, c, d and e be the number of cards with A, B, C, D and E.

If B gives A five cards, A will have as many cards as E.

∴ e = a + 5                                 …(i)

If A gives B five cards, B will have as many cards as D.

∴ d = b + 5                                …(ii)

A and B together have 20 cards more than what D and E have together.

∴ a + b = e + d + 20               …(iii)

It is also given that B has four cards more than what C has and the total number of cards are 201.

∴ b = c + 4 and                        …(iv)

a + b + c + d + e = 201         …(v)

Adding (i) and (ii) we get e + d = a + b + 10 which contradicts equation (iii)

∴ The data given in the question is not correct.

Answer: Option C

Explanation :

Music instructor takes session from 12 noon to 4:00 pm on Monday, Thursday and Sunday.

Sessions of dance instructor are scheduled between 10:00 am to 2:00 pm. on Tuesday, Thursday, Wednesday and Sunday.

Painting instructor takes sessions between 9:00 am to 12:00 noon on Tuesday, Friday and Thursday and between 2:00 pm to 4:00 pm on Wednesday, Saturday and Sunday.

∴ The dance and painting sessions are simultaneously held on days common to the sessions held by dance instructor between 10:00 am to 2:00 pm and the sessions held by the painting instructor between 9:00 am and 12:00 noon i.e. Tuesday and Thursday.

Hence, option (c).

Answer: Option C

Explanation :

As Abhijit already had two increments and during the given period he will get three increments.

Hence his salary on August 1, 2009

= (37400 + 10000)(1.03)⁵

= Rs. 54949.5

≈ Rs. 54950

Hence, option (c).

Answer: Option C

Explanation :

Loss in total emoluments of Nitin

= 23635 × 1.58 – 21000 × 1.58

= Rs. 4163.3 ≈ Rs. 4164

Hence, option (c).

Answer: Option A

Explanation :

Sunitha’s salary before the promotion

= (15600 + 7600)(1.03)(1.58) + 3200

≈ Rs. 49635

After the promotion it will be = (46300)(1.58) + 3200 = Rs. 76354

∴ The required percentage growth = $\left(\frac{76354}{49635}-1\right)$ × 100 = 53.8%

By considering Rs. 3,200 additionally as mentioned in table, under Transport Allowance (TA) it will be

$\left(\frac{79554}{52834}-1\right)$ × 100 = 50.5%

Hence, option (a) or 3.

Answer: Option A

Explanation :

Arrears that Dinesh will get

= (3 × 6)% of 47689 + 8% of 49120

= 8584 + 3930

= Rs. 12514

which is not in the options.

Answer: Option C

Explanation :

If we divide the given input into 5 groups with 2 words each then the groups can be written as:
 
Group 1: Smile Nile

Group 2: Style Mile

Group 3: Shine Wine

Group 4: Mine Swine

Group 5: Bovine Feline

 Group numbers are given in the order in which they are given in that STEP.
 
Then the steps of rearrangement can be written as:

STEP 1: Position of group 4 is interchanged with position of group 5.

STEP 2: Position of group 1 in step 1 is interchanged with position of group 2.

STEP 3: Position of the words of group 3 in step 2 is interchanged.

STEP 4: Position of words of group 1, group 2, group 3 and group 5 are interchanged.
 
For example: If the words in group 1 in step 3 are Smile Nile then the words in group 1 of step 4 will be Nile Smile.

STEP 5: Position of group 1 is interchanged with position of group 2 and position of group 4 is interchanged with position of group 5.

STEP 6: Position of group 4 is interchanged with the position of group 5.

STEP 7: Position of group 1 is interchanged with the position of group 2.
 
∴ We can say that the algorithm of rearrangement repeats after 5 steps.

∴ STEP 8 for the given input will be:
 
STEP 8: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 9: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 10: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

STEP 11: Smile Nile  Style Mile  Shine Wine  Bovine Feline  Mine Swine

STEP 12: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 13: Style Mile  Smile Nile  Wine Shine  Bovine Feline  Mine Swine

STEP 14: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 15: Nile Smile  Mile Style  Wine Shine  Swine Mine  Feline Bovine

STEP 16: Nile Smile  Mile Style  Wine Shine  Feline Bovine  Swine Mine

STEP 17: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 18: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 19: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 20: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

Referring the Steps given in the solution we get that,

STEP 20 is same as the given input.

Hence, option (c).

Answer: Option C

Explanation :

If we divide the given input into 5 groups with 2 words each then the groups can be written as:
 
Group 1: Smile Nile

Group 2: Style Mile

Group 3: Shine Wine

Group 4: Mine Swine

Group 5: Bovine Feline

 Group numbers are given in the order in which they are given in that STEP.
 
Then the steps of rearrangement can be written as:

STEP 1: Position of group 4 is interchanged with position of group 5.

STEP 2: Position of group 1 in step 1 is interchanged with position of group 2.

STEP 3: Position of the words of group 3 in step 2 is interchanged.

STEP 4: Position of words of group 1, group 2, group 3 and group 5 are interchanged.
 
For example: If the words in group 1 in step 3 are Smile Nile then the words in group 1 of step 4 will be Nile Smile.

STEP 5: Position of group 1 is interchanged with position of group 2 and position of group 4 is interchanged with position of group 5.

STEP 6: Position of group 4 is interchanged with the position of group 5.

STEP 7: Position of group 1 is interchanged with the position of group 2.
 
∴ We can say that the algorithm of rearrangement repeats after 5 steps.

∴ STEP 8 for the given input will be:
 
STEP 8: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 9: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 10: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

STEP 11: Smile Nile  Style Mile  Shine Wine  Bovine Feline  Mine Swine

STEP 12: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 13: Style Mile  Smile Nile  Wine Shine  Bovine Feline  Mine Swine

STEP 14: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 15: Nile Smile  Mile Style  Wine Shine  Swine Mine  Feline Bovine

STEP 16: Nile Smile  Mile Style  Wine Shine  Feline Bovine  Swine Mine

STEP 17: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 18: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 19: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 20: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

∴ STEP 14 for the given input is

Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

No option is matching with the STEP 14 but the closest option is option C which should have had Wine Shine instead of Shine Wine.

Hence, option (c).

Answer: Option D

Explanation :

If we divide the given input into 5 groups with 2 words each then the groups can be written as:
 
Group 1: Smile Nile

Group 2: Style Mile

Group 3: Shine Wine

Group 4: Mine Swine

Group 5: Bovine Feline

 Group numbers are given in the order in which they are given in that STEP.
 
Then the steps of rearrangement can be written as:

STEP 1: Position of group 4 is interchanged with position of group 5.

STEP 2: Position of group 1 in step 1 is interchanged with position of group 2.

STEP 3: Position of the words of group 3 in step 2 is interchanged.

STEP 4: Position of words of group 1, group 2, group 3 and group 5 are interchanged.
 
For example: If the words in group 1 in step 3 are Smile Nile then the words in group 1 of step 4 will be Nile Smile.

STEP 5: Position of group 1 is interchanged with position of group 2 and position of group 4 is interchanged with position of group 5.

STEP 6: Position of group 4 is interchanged with the position of group 5.

STEP 7: Position of group 1 is interchanged with the position of group 2.
 
∴ We can say that the algorithm of rearrangement repeats after 5 steps.

∴ STEP 8 for the given input will be:
 
STEP 8: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 9: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 10: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

STEP 11: Smile Nile  Style Mile  Shine Wine  Bovine Feline  Mine Swine

STEP 12: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 13: Style Mile  Smile Nile  Wine Shine  Bovine Feline  Mine Swine

STEP 14: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 15: Nile Smile  Mile Style  Wine Shine  Swine Mine  Feline Bovine

STEP 16: Nile Smile  Mile Style  Wine Shine  Feline Bovine  Swine Mine

STEP 17: Mile Style  Nile Smile  Wine Shine  Feline Bovine  Swine Mine

STEP 18: Mile Style  Nile Smile  Shine Wine  Feline Bovine  Swine Mine

STEP 19: Style Mile  Smile Nile  Shine Wine  Bovine Feline  Mine Swine

STEP 20: Smile Nile  Style Mile  Shine Wine  Mine Swine  Bovine Feline

Referring the Steps given in the solution we get that,

Option A is step 13.

Option B is step 14.

Option C is step 12.

Option D does not fall between step numbers 12 and 14.

Hence, option (d).

Answer: Option C

Explanation :

If the liking of a person is denoted by √ and whatever a person hates is denoted by × then the data given can be represented in a tabular format as:

​​​​​​​

Now, each selected member should share a liking with at least one of the other three selected members and the selected member must also hate at least one of the likings of any of the other persons selected.

Consider option 1:

C1, C2, C5 and C6 cannot be the four people selected by the Prime Minister as C1 hates only River rafting which is not liked by any of the other three.

Consider option 2:

C3, C4, C5 and C6 cannot be the four people selected by the Prime Minister as none of them shares a liking with any other member, also C3 and C6 hate Sightseeing which is not liked by any of them.

Consider option 3:

C1, C2, C4 and C7 are the four people selected by the Prime Minister as all of them share at least one liking with at least one of the three selected members and all of them also hate at least one of the likings of at least one of the selected persons.

Hence, option (c).