IIFT 23 Dec 2021 QA | Previous Year IIFT Paper
Rahul takes 4 days to finish one third of a job, Sohan takes 3 days to finish one sixth of thesame work and Ram takes 5 days to finish half the job. All 3 of them together work for 3 days after whichRahul and Ram leave the job. How long will it take for Sohan to complete the remaining work?
- A.
6 days
- B.
8.1 days
- C.
5.1 days
- D.
7 days
Answer: Option C
Explanation :
From the above information, we can say that Rahul, Sohan and Ram take 12, 18 and 10 days respectively to complete the work alone.
LCM(12, 18, 10) = 180
Let the total work be 180 units
So Work done by Rahul in 1 day = 15 units
Work done by Sohan in 1 day = 10 units
Work done by Ram in 1 day = 18 units
Let the time taken by Sohan to complete the remaining work be x days.
Therefore, 180 = 3*(15 + 10 + 18) + 10x
or, 180 = 129 - 10x
or, x = 5.1 days
Workspace:
A shopkeeper marks up the price of the Toor dal by 20% and gives a discount of 10% to thecustomer. Besides, he also tricks 100 grams to his dealer and his customer respectively while buying orselling 1 kilogram of Toor dal. Find the profit percentage of the shopkeeper.
- A.
22%
- B.
20%
- C.
32%
- D.
27%
Answer: Option C
Explanation :
Let the cost of 1000gm of dal be rupees 1000
Now the shopkeeper is buying 1100 gm of dal for rupees 1000
While selling 900 gm of dal the shopkeeping is charging the price of 1000 gm
Therefore while selling 1100 gm of dal the shopkeeper will charge the price of (1000/900)*1100 gm = 11000/9 gm
He has marked up the price by 20% and then given a discount of 10%
So price charged by shopkeeper = (11000/9)*1.2*0.9 = 1320
So the shopkeeper is spending rupees 1000 to buy the dal and is selling the same quantity of dal at rupees 1320. Therefore, profit percentage is (320/1000)*100 = 32%
Workspace:
For maintaining social distancing due to covid situation, Rohan, Sohan and Rahul are sittingequidistantly, at a distance of 3 meter in a triangular formation. Priya came and sat in between Sohan andRahul such that distance between Priya and Sohan is half the distance between Rahul and Priya. What willbe the distance between Priya and Rohan in meter?
- A.
- B.
- C.
- D.
Answer: Option C
Explanation :
Considering the data given, Rohan, Sohan, and Rahul are sitting in the shape of an equilateral triangle with sides 3m each. Since Priya's distance from Sohan is half her distance from Rahul, she is sitting at a distance of 1 m from Sohan.
Draw a perpendicular AD on BC.
In △ADC, using the Pythagoras theorem,
AC2 = AD2 + DC2
32 = AD2 + 1.52
AD =
In △ADE, using the Pythagoras theorem,
AE2 = AD2 + DE2
AE2 = + = 7
AE =
Hence, the answer is option C.
Workspace:
In a group of students, x number of students drink only Fruit Juice, 2x number of students drinkonly Coke. students drink both Fruit Juice and Coke and the students who drink neither Fruit Juice norCoke are . The number of students who drink Coke may be
- A.
41 and 39
- B.
39 and 54
- C.
59 and 54
- D.
41 and 59
Answer: Option D
Explanation :
No of persons who drink coke = 2x + 57/x
As the no. of persons who drink coke will be an integer so 57/x must be an integer so x can be 1, 3, 19 or 57.
No. of persons who drink neither fruit juice nor coke = 57/3x = 19/x this also should be an integer, so x= 1 or 19 only
When x=1, no. of persons who drink coke = 2+57 = 59
When x=19, no. of persons who drink coke = 38 + 3 = 41
Workspace:
Ishika speaks truth in 60% of cases and Mishika in 85% of cases. Ishika and Mishika agree in astatement. Find the probability that the statement is true.
- A.
- B.
- C.
- D.
Answer: Option D
Explanation :
For both Ishika and Mishika to agree on a statement either both have to speak the truth or both have to speak false.
Probability of both speaking truth = (60/100)*(85/100) = 204/400
Probability of both speaking false = (40/100)*(15/100) = 24/400
The probability that the statement is true when Ishika and Mishika both agree on a statement = (204/400)/{(204/400)+(24/400)} = 204/228 = 51/57
Workspace:
The last two digits of the expression 1(1!)1! + 2(2!)2! + 3(3!)3! + .... + 121(121!)121!
- A.
61
- B.
71
- C.
81
- D.
91
Answer: Option C
Explanation :
From the 5th term onwards the last two of all the terms will 00.
The last two digits of 24 to the power of an even number will be 76 always.
So, last two digits of the above expression will be the last two digits of 1 + 2(2)2 + 3(6)6 + 4(76)
= 1 + 8 + 139968 + 304 = 140281
So last two digits is 81
Workspace:
Two towers 10 meters apart, are 4 m and 6 m high respectively. What will be the height of pointof intersection of lines joining the top of each tower to the bottom of opposite tower?
- A.
2.2 meters
- B.
1.5 meters
- C.
5.5 meters
- D.
2.4 meters
Answer: Option D
Explanation :
Let AB and CD be the towers of length 4m and 6m respectively.
Let the length of BF be x therefore, the length of FC will be 10-x.
Triangle BEF is similar to triangle BDC
So, = =
or, = =
Therefore, EF =
Similarly, triangle EFC is similar to triangle ABC
So, = =
or, = =
Therefore, =
or, x = 4
EF = = 2.4 m
Workspace:
f(x) = where y = f(x). Find the ratio of x to f(y).
- A.
:
- B.
x3 : y3
- C.
1 : 2
- D.
1 : 1
Answer: Option D
Explanation :
f(y) = f(x(x))
or, f(y) = f
f(y) =
or, f(y) = = x
Therefore x : f(y) = 1 : 1
Workspace:
During a marriage ceremony in Panipat, two shots from the air rifle are fired from the sameplace at an interval of 10 minutes 42 seconds. A man sitting in the train which is approaching the placewhere the ceremony is being held, hears the second sound after 10 minutes of hearing the first one.Assuming speed of sound to be 330 m/s, what could be the speed of the train?
- A.
20.1 m/s
- B.
12.4 m/s
- C.
23.1 m/s
- D.
30.1 m/s
Answer: Option C
Explanation :
Distance travelled by the train till the man hears the two shots = 42 × 330 = 13860 m
This distance was travelled by train in 10 minutes or 600 seconds
Speed of train = 13860/600 = 23.1 m/s
Workspace:
If area of the adjacent faces of a cuboid is given as p, q and r respectively and the volume isgiven as 'V' then the square of the volume will be
- A.
pqr
- B.
- C.
- D.
(pqr)2
Answer: Option A
Explanation :
Let the length, breadth and height of the cubhoid be l, b and h respectively.
Therefore of adjacent faces will be lb, bh and hl.
If lb = p, then bh = q and hl = r.
Volume (V) = lbh
V2 = (lbh)2
or, V2 = pqr
Workspace:
If a principal P amounts to A in two years when compounded half yearly with r% interest. The same principal P amounts to A in two years when compounded annually with R% interest, then which of the following relationship is true?
- A.
r > R
- B.
r = R
- C.
r < R
- D.
r ≤ R
Answer: Option C
Explanation :
Since in first case we are compounding half-yearly and in second case we are compounding yearly and the amount received and the principal invested in both the cases is same so interest rate in the first case is lower than the interest rate in the second case.
Workspace:
In the galaxy “Andromeda”, a planet named “Exo” has a city called “Azith”. The city has analphabet system that consists of 48 letters and an octo-decimal number system (base -18). Theregistration number on the number plate of a vehicle in the city has two parts. The first part is the alphabetpart that consists of three letters and the second part is the number part that consists of 3 digits. The cityadministration issues all kinds of registration numbers with following restrictions:
a. The letters in the alphabet part are in ascending order and all letters must be distinct.
b. In the number part, the first digit is three more than the third digit.
Find the number of possible registration numbers available in the Azith city.
- A.
3353270
- B.
257830
- C.
5339840
- D.
4669920
Answer: Option D
Explanation :
There are 48 alphabets out of which we need 3
So, no. of ways of selecting 3 alphabets from 48 alphabets is 48C3
Since we need to arrange these alphabets in ascending order so there is only one possible way for every three alphabets.
The first digit is 3 more than the third digit.
For a particular first digit there will be a particular third digit but the 2nd digit can be any of the numbers
So, no. of ways of selecting first digit = 15
No. of ways of selecting 2nd digit = 18
Therefore, total no. of ways = 48C3 × 15 × 18 = 4669920
Workspace:
The radius of circle is increased in a way such that its circumference increases by 8%. By howmuch percentage the area of the circle increases?
- A.
12.5%
- B.
16.64%
- C.
10.5%
- D.
6.4%
Answer: Option B
Explanation :
Increase in circumference is 8% which means that the increase in radius is also 8%
Increase in area = 8 + 8 + (8*8)/100 = 16 + 0.64 = 16.64%
Workspace:
A group of 78 people watch NDTV, Times Now and Republic. Out of these news channels, 36 watch NDTV, 48 watch Times Now and 32 watches Republic. 14 people watch both NDTV and Times Now,20 people watch both Times Now and Republic, and 12 people watch both Republic and NDTV. Find the ratioof the number of people who watch only Times Now to the number of people who watch only Republic.
- A.
9 : 4
- B.
13 : 21
- C.
11 : 4
- D.
17 : 4
Answer: Option C
Explanation :
P (A U B U C) = P (A) + P (B) + P (C) − {P (A ∩ B) + P (B ∩ C) + P (C ∩ A)} + P (A ∩ B ∩ C)
Let the no. of people who watch all three be x
78 = 36 + 48 + 32 - (14 + 20 + 12) + x
or x = 8
No. of people who watch times now only = 48 - (14 + 20) + 8 = 22
No. of people who watch republic only = 32 - (20 + 12) + 8 = 8
Ratio = 22/8 = 11 : 4
Workspace:
Find the set S that denotes the set of all values of 'α' for which the roots of the equation (1 - α)x2 - 6αx + 8α = 0 is greater than 2.
- A.
- B.
- C.
- D.
Answer: Option D
Explanation :
αf(x) = (1 - α)x2 - 6αx + 8α = 0
Now roots are greater than 2 therefore,
> 2
f(2) > 0
D > 0
> 0
2(1 - α) > 0
< 0
α ∈ (0, 1)
f(2) > 0
(1 − α ) 4 − 12α + 8α > 0
4 − 8α > 0
a <
D > 0
36α2 - 32α (1 - α) > 0
68α2 - 32α > 0
α(68α - 32) > 0
α ∈ (-∞, 0) ∪
Taking the intersection of all we get α ∈
Workspace:
Evaluate:
[cos2 + cos2 + cos2 + ... + cos2 ] - [sin2 + sin2 + ... + sin2 ]
- A.
1
- B.
- C.
- D.
2
Answer: Option B
Explanation :
cos (A) = sin
sin A = cos
cos = sin = sin
sin2 (A) + cos2 (A) = 1
So the series simplifies to (1 + 1 + 1 + 1) - (1 + 1 + 1 + 1/2)
therefore value of series is 1/2
Workspace:
Same item is sold for Rs. 600 and Rs. 175, respectively. The profit earned on the first sale is 20times the loss incurred on the second sale. To make an overall profit of 30% in the whole transaction, atwhat price the second sale should happen:
- A.
Rs. 310 approx
- B.
Rs. 238 approx
- C.
Rs. 254 approx
- D.
Rs. 357 approx
Answer: Option C
Explanation :
Let the CP be x
Now as per question, 600 - x = 20(x - 175)
21x = 4100
x = 195.24
Therefore, to make a profit of 30% selling price of second article should be = 1.3 × 195.24 = 253.81
Workspace:
An unbiased dice is tossed seven times. Find the probability of getting a third six on the seventh throw.
- A.
- B.
- C.
- D.
Answer: Option B
Explanation :
We need a third 6 in the 7th throw which means that in the first 6 throws we should get 6 exactly twice.
No. of ways of getting 6 exactly twice in first 6 throws = 6C2
Probability of getting 6 for the third time in the seventh throw =
Workspace:
There are 12 points in a two-dimensional plane with following coordinates: Points A, B, C, D, E,F, G have coordinates (1, 0), (2, 0), (3, 0), (4, 0), (5, 0), (6, 0) and (7, 0) respectively. Points H, I, J havecoordinates (1, 1), (2, 2) and (3, 3) respectively. Points K, L have coordinates (4, -2) and (5, -3)respectively. The number of circles possible with these points are?
- A.
179
- B.
158
- C.
168
- D.
147
Answer: Option A
Explanation :
A, B, C, D, E, F, G all lie of a single line
H, I, J all lie on another single line
K, L lie on another single line
If we are given three points which are not collinear than we can draw a circle from these three points
Workspace:
“xyz” and “zyx” are three digit numbers where x, y, z are distinct digits from 0 to 9. Differenceof xyz and zyx has a factor of 7.
What is the maximum possible value of the LCM of x, y and z?
- A.
126
- B.
72
- C.
90
- D.
56
Answer: Option A
Explanation :
The difference between the numbers xyz and zyx will be a multiple of 99. therefore, 99(x - z) = 99*7
x - z = 7
No to maximise the LCM of x, y, z we can take x = 9, y = 7 and z = 2
Therefore LCM = 126
Workspace:
The value of x which satisfy 6 - 9 log8 - 8( - = 0 is
- A.
2
- B.
- C.
4
- D.
8
Answer: Option D
Explanation :
6 - 9 log8 - 8 - = 0
6 - log2 4 + log2 x - 2 - 2 = 0
Let be t.
4 + t3 - 2t2 - 2t = 0
or, (t - 2) (t2 - 2) = 0
so, t = 2 or
log2 x = 8
Workspace:
Three small identical circles are inscribed inside an equilateral triangle with length 10 cm as shown in the figure. The radius of each small circle is 2 cm A big circle touches these three circles as shown in the figure. Find the ratio of the area of the big circle with that of the area of the small circle. (figure not as per scale)
- A.
4 : 1
- B.
2 : 1
- C.
3 : 1
- D.
5 : 1
Answer: Option A
Explanation :
Height of triangle = (10) × = 15
Distance between the centroid of the triangle and the vertex = 15 × = 10
Since in-radius is one-third of the height of the triangle
therefore, length of the line from vertex to the point where small circle and big circle touch each other = 10 - 6 = 4 cm
Radius of the bigger circle = 10 - 6 = 4 cm
Ratio of areas will be square of the ration of radius which is 4 : 1
Workspace:
Abdul can go from his home to his favourite basketball ground by taking any of the two roads represented by y - x = 10 and 2x + 2y = 15. The ground is located at a distance of 200 units from each of the roads. What is the possible location of the basketball ground?
- A.
(-1.25 + 200, 8.75)
- B.
(-125 + , 8.75 + )
- C.
(-1.25 + 100, 8.75 + 100)
- D.
(-1.25 + 100, 8.75 + 100)
Answer: Option A
Explanation :
Distance of point (-1.25 + 200, 8.75) from lines y - x = 10 and x + y = 15/2
Distance from y - x = 10 is = 200
Distance from x + y = 15/2 is + = 200
Workspace:
The rate at which coal is consumed by a RORO train, which is operated by Konkan Railways,fluctuates as the square of the speed. It is given that coal consumption of this train is 1200 kg/hour whenthe speed is 40 km/hour. Konkan Railway bears the cost of coal at the rate Rs. 16/100kg and all otherexpenses of running the RORO train costs Konkan Railways Rs. 13/hour. Find the total cost in paise/km, foroperating the RORO train when it is running at the speed of V km/hour.
- A.
1300 + 5V2
- B.
1300 + 12V2
- C.
1300 + 75V2
- D.
1300 + 16V2
Answer: Option B
Explanation :
Let rate of consumption per hour be R
Therefore, R = k(V2)
When speed = 40km/hr R = 1200 kg/hr
So, When speed = V
R = × V2
Cost of coal consumed per hour = × V2 × = V2
All other expenses = Rs. 13/ hr
Therefore operating cost per hour = Rs. (13 + V2)
Operation cos in paise per hour = 1300 + 12V2
Workspace:
A can was full of olive oil. Lata draws each time 20% of the volume from the can and replaceswith groundnut oil. Usha draws 10% of the volume and replaces with mustard oil. Starting with Lata, bothrepeats the procedure alternatively two times each. What is the ratio of olive oil, groundnut oil and mustardoil in the end?
- A.
7200 : 1800 : 1000
- B.
5184 : 3096 : 1720
- C.
5760 : 3440 : 800
- D.
5436 : 3284 : 1280
Answer: Option B
Explanation :
Percentage of olive oil in the mixture = 100 × × × × = 51.84%
Workspace:
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