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Question:

ABCDE play a game of cards. ‘A’ tells ‘B’ that if ‘B’ gives him five cards ‘A’ will have as many cards as ‘E’ has. However if A gives five cards to ‘B’ then ‘B’ will have as many cards as ‘D’. A and B together has 20 cards more than what D and E have together. B has four cards more than what C has and total number of cards are 201. How many cards B have?

Explanation:

Data given in the question is not correct.

Let a, b, c, d and e be the number of cards with A, B, C, D and E.

If B gives A five cards, A will have as many cards as E.

∴ e = a + 5                                 …(i)

If A gives B five cards, B will have as many cards as D.

∴ d = b + 5                                …(ii)

A and B together have 20 cards more than what D and E have together.

∴ a + b = e + d + 20               …(iii)

It is also given that B has four cards more than what C has and the total number of cards are 201.

∴ b = c + 4 and                        …(iv)

a + b + c + d + e = 201         …(v)

Adding (i) and (ii) we get e + d = a + b + 10 which contradicts equation (iii)

∴ The data given in the question is not correct.