Algebra - Logarithms - Previous Year IPM/BBA Questions
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The product of the roots of the equation - 5log2 x + 6 = 0
Answer: 32
Text Explanation :
Here, let log2x = a
The given equation can be written as:
a2 × log22 - 5a + 6 = 0
⇒ a2 - 5a + 6 = 0 [log22 = 1]
⇒ a2 - 3a - 2a + 6 = 0
⇒ a(a - 3) - 2(a - 3) = 0
⇒ (a - 3)(a - 2) = 0
⇒ a = 2 or 3
⇒ log2x = 2 or log2x = 3
⇒ x = 22 or x = 23
⇒ x = 4 or x = 8
∴ Required product of the roots = 4 × 8 = 32
Hence, 32.
Workspace:
Let a, b, c be real numbers greater than 1. and n be a positive real number not equal to I. If logn(log2 a) = 1, logn(log2b) = 2 and logn(log2c) = 3. then which of the following is true?
- (a)
(an + b)n = ac
- (b)
an + bn = cn
- (c)
a + b = c
- (d)
(b - a)n = (c - b)
Answer: Option A
Text Explanation :
Workspace:
If logcosxsinx + logsinxcosx = 2, then the value of x is
- (a)
nπ/4 + π/4, n is an integer
- (b)
2nπ + π/4, n is an integer
- (c)
nπ + π/4, n is an integer
- (d)
nπ/4, n is an integer
Answer: Option B
Text Explanation :
Workspace:
+ = 1 and y = x2 - 30, then the value of x2 + y2 is:
Answer: 72
Text Explanation :
Given, + = 1
⇒ + = 1
⇒ logxy + logyx = 2
Now, logxy and logyx are reciprocal of each other and their sum is 2. Sum of a number and its reciprocal is always greater than or equal to 2. Equality is true when the number and reciprocal are both equal to 1.
∴ logxy = 1
⇒ x = y
Now, y = x2 - 30 [y = x]
⇒ x2 - x - 30 = 0
⇒ (x - 6)(x + 5) = 0
⇒ x = 6 [x = -5 is rejected as log is not defined for negative numbers.]
∴ y = 6
∴ x2 + y2 = 62 + 62 = 72
Hence, 72.
Workspace:
The set of real values of x for which the inequality ≤ < holds is
- (a)
[2, 81)
- (b)
(2, 27)
- (c)
[2, 81]
- (d)
(2, 27]
Answer: Option A
Text Explanation :
Given, ≤ <
⇒ ≤ <
⇒ ≤ <
⇒ ≤ <
⇒ ≤ < 4
⇒ ≤ <
⇒ 2 ≤ x < 81
∴ x ∈ [2, 81)
Hence, option (a).
Workspace:
Suppose that log2[log3(log4a)] = log3[log4(log2b)] = log4[log2(log3c)] = 0 then the value of a + b + c is
- (a)
105
- (b)
71
- (c)
89
- (d)
37
Answer: Option C
Text Explanation :
Given, log2[log3(log4a)] = log3[log4(log2b)] = log4[log2(log3c)] = 0
⇒ log2[log3(log4a)] = 0
⇒ log3(log4a) = 20 = 1
⇒ log4a = 31 = 3
⇒ a = 43 = 64
Also, log3[log4(log2b)] = 0
⇒ log4(log2b) = 30 = 1
⇒ log2b = 41 = 4
⇒ b = 24 = 16
Also, log4[log2(log3c)] = 0
⇒ log2(log3c) = 40 = 1
⇒ log3c = 21 = 2
⇒ c = 32 = 9
∴ a + b + c = 64 + 16 + 9 = 89.
Hence, option (c).
Workspace:
The value of is _________.
Answer: 16
Text Explanation :
Given,
=
=
=
=
=
=
=
=
=
= 16.
Hence, 16.
Workspace:
If log5log8(x2 - 1) = 0, then a possible value of x is
- (a)
2√2
- (b)
√2
- (c)
2
- (d)
3
Answer: Option D
Text Explanation :
Given, log5log8(x2 - 1) = 0
⇒ log8(x2 - 1) = 50 = 1
⇒ (x2 - 1) = 81
⇒ x2 = 9
⇒ x = +3 or -3.
Hence, option (d).
Workspace:
Given f(x) = x2 + log3x and g(y) = 2y + f(y), then the value of g(3) equals
- (a)
16
- (b)
15
- (c)
25
- (d)
26
Answer: Option A
Text Explanation :
Given, f(x) = x2 + log3x and g(y) = 2y + f(y),
∴ g(3) = 2 × 3 + f(3)
⇒ g(3) = 2 × 3 + 32 + log33
⇒ g(3) = 6 + 9 + 1 = 16
Hence, option (a).
Workspace:
Suppose that a, b, and c are real numbers greater than 1. Then the value of + + is
Answer: 3
Text Explanation :
Workspace:
If x, y, z are positive real numbers such that x12 = y16 = z24,and the three quantities 3logyx, 4logzy, nlogxz are in arithmetic progression, then the value of n is
Answer: 16
Text Explanation :
Workspace:
The inequality < 1 holds true for
- (a)
x ∈ (1/3, 1)
- (b)
x ∈ (1/3, 2)
- (c)
x ∈ (0, 1/3) ∪ (1, 2)
- (d)
x ∈ (-∞, 1)
Answer: Option A
Text Explanation :
Workspace:
The value of log330−1 + log4900−1 + log530−1 is
- (a)
0.5
- (b)
30
- (c)
2
- (d)
1
Answer: Option D
Text Explanation :
Workspace: