SSC CHSL 10th June Shift 3 Previous Year Paper Quantitative Aptitude questions | CHSL Past Year Papers

1. SSC CHSL 10th June Shift 3 - QA | Tables & Graphs - SSC

In a school of 200 students, the following chart represents the percentage of students involved in different sports.

What is the number of students playing cricket?

A.
17
B.
83
C.
24
D.
34

2. SSC CHSL 10th June Shift 3 - QA | Average, Mixture & Alligation - SSC

The mean of five numbers is 18. If one number is excluded, their mean is 16. The excluded number is:

A.
36
B.
32
C.
26
D.
30

3. SSC CHSL 10th June Shift 3 - QA | Tables & Graphs - SSC

The table below shows the number of cakes sold by six different bakeries in a town on five different days of particular week.

What is the total number of cakes sold by the bakery D on Monday, Thursday and Sunday, taken together?

A.
779
B.
668
C.
530
D.
686

4. SSC CHSL 10th June Shift 3 - QA | Tables & Graphs - SSC

Observe the graph and answer the question that follows.

How many students obtained marks more than 130?

A.
19
B.
14
C.
17
D.
20

5. SSC CHSL 10th June Shift 3 - QA | Ratio, Proportion & Variation - SSC

A varies jointly with B and C. A = 6 when B = 3 and C = 2. Find A when B = 5 and C = 7.

A.
105
B.
70
C.
17.5
D.
35

Answer: Option D

Explanation :

A ∝ B × C

⇒ $\frac{A}{B \times C}$ = constant

∴ $\frac{6}{3 \times 2}$ = $\frac{A}{5 \times 7}$

⇒ A = 35

Hence, option (d).

6. SSC CHSL 10th June Shift 3 - QA | Average, Mixture & Alligation - SSC

A shopkeeper purchases 20000 units of a product at ₹1 each, 15000 units at ₹1.15 each and 5000 units at ₹2 each. What is the weighted average price of one unit?

(Correct to two decimal places)

A.
₹1.20
B.
₹1.36
C.
₹1.38
D.
₹1.18

Answer: Option D

Explanation :

Weighted average price = $\frac{Total cost}{Total quantity}$ = $\frac{20, 000 \times 1 + 15, 000 \times 1.15 + 5, 000 \times 2}{20, 000 + 15, 000 + 5, 000}$ = $\frac{47, 250}{40, 000}$ = Rs. 1.18

Hence, option (d).

7. SSC CHSL 10th June Shift 3 - QA | Time, Speed & Distance - SSC

After seeing a policeman from a distance of 500 m, a thief starts running at a speed of 10 km/h. After noticing, the policeman chases immediately with a speed of 12 km h, and the thief is caught. The distance run by the policeman is:

A.
3.6 km
B.
2.5 km
C.
3 km
D.
2.4 km

8. SSC CHSL 10th June Shift 3 - QA | Average, Mixture & Alligation - SSC

The average of 10 observations is 21. A new observation is included and the average of these 11 numbers is 1 less than the prevoius average. The observation is ______.

A.
11
B.
10
C.
21
D.
12

9. SSC CHSL 10th June Shift 3 - QA | Mensuration - SSC

The diameter of the base of a right-circular cylinder is 12 cm and the height of the cylinder is 2.45 times the radius of its base. Find the curved surface area of the cylinder.

[Use $π = \frac{22}{7}$ ]

A.
554.4 cm²
B.
552.4 cm²
C.
556.4 cm²
D.
544.4 cm²

10. SSC CHSL 10th June Shift 3 - QA | Simple Equation - SSC

One number x is thrice the other number y. If the sum of both the numbers is 20, then what is the values of x and y are respectively ?

A.
8 and 12
B.
5 and 15
C.
15 and 5
D.
2 and 18

11. SSC CHSL 10th June Shift 3 - QA | Percentage, Profit & Loss - SSC

A pen passing through two hands is finally sold at a profit of 44% of the original cost price. If the first dealer makes a profit of 20%, then the profit made by the second dealer is:

A.
24%
B.
36%
C.
20%
D.
27%

Answer: Option C

Explanation :

Let the original cost prime of the pen = Rs. 100

First person sells the pen for 20% profit, hence selling price for first person = Rs. 120 [This is the cost price for 2^nd person.]

Now, overall the price increases by 44% after 2 hands, it means the second person sold the pen for Rs. 144.

∴ Profit of 2^nd person = $\frac{144 - 120}{120}$ × 100 = 20%

Hence, option (c).

12. SSC CHSL 10th June Shift 3 - QA | Number Theory - SSC

Which of the following is the least 6-digit number that is divisible by 93?

A.
100065
B.
100070
C.
100075
D.
100068

13. SSC CHSL 10th June Shift 3 - QA | Simple & Compound Interest - SSC

A sum of ₹14,375, when invested at r% interest per year compounded annually, amounts to ₹16,767 after two years. What is the value of r?

A.
9
B.
8
C.
7
D.
6

Answer: Option B

Explanation :

Given, 16767 = 14375 ${(1 + \frac{r}{100})}^{2}$

⇒ ${(1 + \frac{r}{100})}^{2}$ = $\frac{16767}{14375}$

⇒ ${(1 + \frac{r}{100})}^{2}$ = 1.1664

⇒ $(1 + \frac{r}{100})$ = 1.08

⇒ r = 8%

Hence, option (b).

14. SSC CHSL 10th June Shift 3 - QA | Percentage, Profit & Loss - SSC

Under a discount scheme, a dozen pair of gloves quoted at ₹200 is available at a discount of 20%. How many pairs of gloves can be bought for ₹320?

A.
20
B.
15
C.
18
D.
24

15. SSC CHSL 10th June Shift 3 - QA | Simplification - SSC

Which of the following options has the greatest value?

A.
(−99) + (−44) − 12
B.
20 + 4 + (−8) − 2 + 3 + 6
C.
(−18) − 45 + (− 3 − 2)
D.
(−22) + (− 4 − 7)

16. SSC CHSL 10th June Shift 3 - QA | Time, Speed & Distance - SSC

Ravi drove for 4 hours at a speed of 70 miles per hour and for 2 hours at 40 miles per hour. What was his average speed (in miles per hour) for the whole journey?

A.
50
B.
60
C.
55
D.
45

17. SSC CHSL 10th June Shift 3 - QA | Triangles - SSC

In ΔABC, if G is the centroid and AD is a median with length 9 cm, then the length of AG is:

A.
5 cm
B.
6 cm
C.
8 cm
D.
7 cm

18. SSC CHSL 10th June Shift 3 - QA | Percentage, Profit & Loss - SSC

A person could save 20% of his income. A year later, his income increased by 25% but he could save the same amount only as before. By what percentage has his expenditure increased?

A.
29.75 %
B.
31.25 %
C.
27.5 %
D.
32.5 %

Answer: Option B

Explanation :

Let the initial income of the person be Rs. 100.
∴ His initial savings = 20% of income = Rs. 20
∴ His initial expenditure = 100 - 20 = Rs. 80

New income of the preson is 25% more than initial income = Rs. 125
∴ His new savings is same = Rs. 20
∴ His new expenditure = 125 - 20 = Rs. 105

⇒ % Increase in his expenditure = $\frac{105 - 80}{80}$ × 100 = 31.25%

Hence, option (b).

19. SSC CHSL 10th June Shift 3 - QA | Number Theory - SSC

What is the product of (x + a) and (x + b)?

A.
x² + (a - b) x + ab
B.
x² + (a - b) x - ab
C.
x² + (a + b) x + ab
D.
x² + (a - b) x - ab

20. SSC CHSL 10th June Shift 3 - QA | Number Theory - SSC

If x + y + z = 10, x² + y² + z² = 30, then the value of x³ + y³ + z³ - 3xyz is ________.

A.
-10
B.
-70
C.
-50
D.
-30

21. SSC CHSL 10th June Shift 3 - QA | Mensuration - SSC

What is the height of a solid right circular cylinder whose radius is 3 cm and total surface area is 60π cm²?

A.
3 cm
B.
9 cm
C.
7 cm
D.
5 cm

22. SSC CHSL 10th June Shift 3 - QA | Trigonometry - SSC

The value of sin 73° + cos 137° is:

A.
cos 13°
B.
sin 13°
C.
cos 18°
D.
sin 18°

Answer: Option B

Explanation :

We know, sin A - sin B = 2 × $\cos (\frac{A + B}{2})$ × $\sin (\frac{A - B}{2})$

Given, sin 73° + cos 137° = sin 73° + cos (90 + 47)° = sin 73° - sin 47°

⇒ sin 73° - sin 47° = 2 × $\cos (\frac{73 + 47}{2})$ × $\sin (\frac{73 - 47}{2})$

⇒ sin 73° - sin 47° = 2 × cos 60° × sin 13°

⇒ sin 73° - sin 47° = 2 × 1/2 × sin 13°

⇒ sin 73° - sin 47° = sin 13°

Hence, option (b).

23. SSC CHSL 10th June Shift 3 - QA | Triangles - SSC

What is the area (in cm²) of an equilateral triangle of side 20 cm?

A.
100√3
B.
200
C.
100√2
D.
100

Answer: Option A

Explanation :

Area of an equilateral triangle = $\frac{\sqrt{3}}{4} a^{2}$ [where a is the side of the triangle]

∴ Required area = $\frac{\sqrt{3}}{4} \times 20^{2}$ = 100√3

Hence, option (a).

24. SSC CHSL 10th June Shift 3 - QA | Time & Work - SSC

45 people can repair a road in 10 days, working 6 hours a day. In how many days can 30 people, working 6 hours a day, complete the same work?

A.
15
B.
12
C.
10
D.
18

25. SSC CHSL 10th June Shift 3 - QA | Percentage, Profit & Loss - SSC

The marked price of a table fan is ₹3,750 and is available to the retailer at a discount of 20%. At what price should the retailer sell it to earn a profit of 15%?

A.
₹3,450
B.
₹3,350
C.
₹3,300
D.
₹3,400

SSC CHSL 10th June Shift 3 - QA

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