Discussion

Explanation:

Given, 16767 = 14375${\left(1+\frac{\mathrm{r}}{100}\right)}^2$

⇒ ${\left(1+\frac{\mathrm{r}}{100}\right)}^2$ = $\frac{16767}{14375}$

⇒ ${\left(1+\frac{\mathrm{r}}{100}\right)}^2$ = 1.1664

⇒ $\left(1+\frac{\mathrm{r}}{100}\right)$ = 1.08

⇒ r = 8%

Hence, option (b).

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