SSC CHSL 10th June Shift 2 Previous Year Paper Quantitative Aptitude questions | CHSL Past Year Papers

1. SSC CHSL 10th June Shift 2 - QA | Number Theory - SSC

What is the smallest natural number that should be added to 54321 so that the sum is divisible by 6?

A.
7
B.
3
C.
1
D.
5

2. SSC CHSL 10th June Shift 2 - QA | Ratio, Proportion & Variation - SSC

Rice worth ₹96 per kg and ₹104 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth ₹113 per kg, the price of the third variety of rice per kg will be:

A.
₹109
B.
₹128
C.
₹126
D.
₹117

3. SSC CHSL 10th June Shift 2 - QA | Mensuration - SSC

How many spherical balls of radius 5 cm can be made by melting a spherical clay ball having a radius of 15 cm?

A.
3
B.
27
C.
9
D.
18

4. SSC CHSL 10th June Shift 2 - QA | Simple & Compound Interest - SSC

Find the compound interest on ₹5,50,000 at 7% per annum for 2 years, compounded annually.

A.
₹79,695
B.
₹80,605
C.
₹62,695
D.
₹79,690

5. SSC CHSL 10th June Shift 2 - QA | Time & Work - SSC

A and B together can finish a job in 40 days. A can do the same job on her own in 60 days. How long will B take to do the three-fourth of the same work all alone?

A.
120 days
B.
80 days
C.
90 days
D.
100 days

Answer: Option C

Explanation :

Let the total work to be done = LCM(40, 60) = 120 units.

Efficiency of A alone = 120/60 = 2 units/day

Efficiency of A and B together = 120/40 = 3 units/day

∴ Efficiency of B alone = 3 - 2 = 1 unit/day

⇒ Time taken by B alone to complete the work = 120/1 = 120 days.

⇒ Time taken by B alone to complete 3/4th work = 120 × 3/4 = 90 days.

Alternately,
Let B taken B days to complete the work alone.

⇒ $\frac{1}{40}$ = $\frac{1}{60}$ + $\frac{1}{B}$

⇒ $\frac{1}{40}$ - $\frac{1}{60}$ = $\frac{1}{B}$

⇒ $\frac{1}{B}$ = $\frac{3 - 2}{120}$

⇒ B = 120

⇒ Time taken by B alone to complete 3/4th work = 120 × 3/4 = 90 days.

Hence, option (c).

6. SSC CHSL 10th June Shift 2 - QA | Average, Mixture & Alligation - SSC

The average monthly expenditure of a family for the first four months is ₹13,750, for the next three months is ₹11,750 and for the last five months is ₹31,750. If the family saves ₹15,550 during the whole year, find the average monthly income of the family during the year.

(Consider integral part only)

A.
₹21,055
B.
₹22,045
C.
₹22,000
D.
₹23,040

7. SSC CHSL 10th June Shift 2 - QA | Percentage, Profit & Loss - SSC

Successive discounts of 10% and 20% are given on the purchase of a purse . If the price of the purse is ₹2,250, find the selling price.

A.
₹1,620
B.
₹1,320
C.
₹1,290
D.
₹1,520

8. SSC CHSL 10th June Shift 2 - QA | Quadrilaterals & Polygons - SSC

The base of a parallelogram is twice as long as its corresponding height. If the area of the parallelogram is 144 , find the mentioned height.

A.
6√2 cm
B.
3√2 cm
C.
2√2 cm
D.
8√2 cm

9. SSC CHSL 10th June Shift 2 - QA | Tables & Graphs - SSC

A householder spent his monthly salary of ₹7,200 on different items. If he spent ₹4,000 on food and ₹400 on education, then the central angles respectively are:

A.
30°, 60°
B.
50°, 200°
C.
200°, 20°
D.
200°, 60°

10. SSC CHSL 10th June Shift 2 - QA | Average, Mixture & Alligation - SSC

A shopkeeper mixes three types of rice costing ₹50 per kg, ₹60 per kg and ₹75 per kg in the ratio of 3 : 1 : 2. The average cost of the mixture per kg is:

A.
₹ 50
B.
₹ 75
C.
₹ 60
D.
₹ 65

Answer: Option C

Explanation :

Let the quantity mixed is 3 kgs, 1 kg and 2 kgs respectively.

∴ Average cost per kg = $\frac{3 \times 50 + 1 \times 60 + 2 \times 75}{3 + 1 + 2}$ = $\frac{360}{6}$ = Rs. 60/kg

Hence, option (c).

11. SSC CHSL 10th June Shift 2 - QA | Tables & Graphs - SSC

Study the given bar-chart and answer the question that follows. The bar chart shows the production and sale of cars (in thousands) over the years 2011 to 2015

The percentage by which sales exceeds production in 2014 is:

A.
35
B.
25
C.
20
D.
30

12. SSC CHSL 10th June Shift 2 - QA | Triangles - SSC

One of the angles of a triangle is 108°, and the other two angles are equal. What is the measure of each of these equal angles?

A.
36°
B.
72°
C.
78°
D.
39°

13. SSC CHSL 10th June Shift 2 - QA | Simplification - SSC

What is the value of 12 - 8 ÷ 2 - {16 of - 2 + 3 × 5 - 4}?

A.
0
B.
1
C.
45
D.
29

14. SSC CHSL 10th June Shift 2 - QA | Simple & Compound Interest - SSC

A sum of ₹5,000 was deposited for 3 years at 10% per annum, compounded annually. The difference between the interest for 2 years and that for 3 years is:

A.
₹506
B.
₹605
C.
₹560
D.
₹650

Answer: Option B

Explanation :

Interest for 2 years = 5,000 ${(1 + \frac{10}{100})}^{2}$ - 5000 = 6050 - 5000 = Rs. 1,050

Interest for 3 years = 5,000 ${(1 + \frac{10}{100})}^{3}$ - 5000 = 6655 - 5000 = Rs. 1,655

Difference in interest for 3 years and 2 years = 1655 - 1050 = Rs. 605

Hence, option (b).

15. SSC CHSL 10th June Shift 2 - QA | Time, Speed & Distance - SSC

‘A’ and ‘B’ are two stations 494 km apart. A train starts from station ‘A’ at 3 p.m. and travels towards station ‘B’ at 83 km/h. Another train starts from station ‘B’ at 4 p.m. and travels towards station ‘A’ at 54 km/h. At what time do they meet?

A.
7 p.m.
B.
9 a.m.
C.
7 a.m.
D.
8 p.m

Answer: Option A

Explanation :

Distance travelled by A till 4 pm = 83 × 1 = 83 kms.

Distance between A and B at 4 pm = 494 - 83 = 411 kms

Relative speed of A and B after 4 pm = 83 + 54 = 137 km/hr

∴ Time taken for A and B to meet = $\frac{Relative Distance between them}{Their relative speed}$ = $\frac{411}{137}$ = 3 hours.

∴ They meet 3 hours after 4 pm i.e., at 7 pm.

Hence, option (a).

16. SSC CHSL 10th June Shift 2 - QA | Percentage, Profit & Loss - SSC

One single discount which is equivalent to 20%, 10% and 5% is given by:

A.
32.60%
B.
31.60%
C.
30.60%
D.
32.80%

17. SSC CHSL 10th June Shift 2 - QA | Simplification - SSC

Simplify the fo llowing expression.

$\frac{(62 \times 62 \times 62) - 3 (62 \times 62 \times 22) + 3 (62 \times 22 \times 22) - (22 \times 22 \times 22)}{8 \times 8 \times 8}$

A.
1250
B.
25
C.
125
D.
225

Answer: Option C

Explanation :

$\frac{(62 \times 62 \times 62) - 3 (62 \times 62 \times 22) + 3 (62 \times 22 \times 22) - (22 \times 22 \times 22)}{8 \times 8 \times 8}$

$\frac{62^{3} - 3 \times 62^{2} \times 22 + 3 \times 62 \times 22^{2} - 22^{3}}{8^{3}}$

We know, (a - b)³ = a³ - 3a²b + 3ab² - b³

∴ 62³ - 3 × 62²× 22 + 3 × 62 × 22² - 22³ = (62 - 22)³

∴ $\frac{{(62 - 22)}^{3}}{8^{3}}$ = $\frac{40^{3}}{8^{3}}$ = 53 = 125

Hence, option (c).

18. SSC CHSL 10th June Shift 2 - QA | Percentage, Profit & Loss - SSC

P sold an item to Q at a 20% gain, and Q sold it to R at a loss of 10%. If R bought the item for ₹1,080, then at what price did P purchase it?

A.
₹1000
B.
₹5000
C.
₹3000
D.
₹800

19. SSC CHSL 10th June Shift 2 - QA | Trigonometry - SSC

If cot θ = cot 30° cot 60° and θ is an acute angle, then 2θ is equal to:

A.
45°
B.
60°
C.
30°
D.
90°

20. SSC CHSL 10th June Shift 2 - QA | Number Theory - SSC

For what value(s) of k will the expression p + $\frac{1}{9} \sqrt{p}$ + $k^{2}$ have equal roots.

A.
$k = \pm \frac{1}{21}$
B.
$k = \pm \frac{1}{18}$
C.
$k = \pm \frac{1}{9}$
D.
$k = \pm \frac{1}{8}$

21. SSC CHSL 10th June Shift 2 - QA | Tables & Graphs - SSC

The following bar graph shows the sales (in thousands) of books from six different branches of a publishing company in 2000 and 2001.

Answer the following question based on the bar graph:

What is the ratio of the total sales of C3 for both years to the total sales of C4 for both years?

A.
14 : 15
B.
15 : 14
C.
13 : 14
D.
12 : 13

22. SSC CHSL 10th June Shift 2 - QA | Percentage, Profit & Loss - SSC

In a panchayat election Candidate A secured 30% of the total votes and did NOT qualify by 6 votes. Candidate B secured 40% of the total votes and got 6 votes more than the bare minimum to qualify. The total number of votes were _________.

A.
100
B.
160
C.
140
D.
120

23. SSC CHSL 10th June Shift 2 - QA | Number Theory - SSC

If x + 2y = 10 and 2xy = 9, then one of the value of x − 2y is:

A.
10
B.
12
C.
6
D.
8

24. SSC CHSL 10th June Shift 2 - QA | Mensuration - SSC

What is the surface area of a sphere whose diameter is 30 cm?

[Use π = 3.14.]

A.
1413
B.
1130
C.
2826
D.
1134

25. SSC CHSL 10th June Shift 2 - QA | Ratio, Proportion & Variation - SSC

What is the mean proportional between 64 and 4096?

A.
8
B.
512
C.
128
D.
192

Answer: Option B

Explanation :

Let mean proportion be x.

∴ $\frac{64}{x}$ = $\frac{x}{4096}$

⇒ x² = 64 × 4096

⇒ x = 8 × 64 = 512

Hence, option (b).

SSC CHSL 10th June Shift 2 - QA

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