In a panchayat election Candidate A secured 30% of the total votes and did NOT qualify by 6 votes. Candidate B secured 40% of the total votes and got 6 votes more than the bare minimum to qualify. The total number of votes were _________.
Explanation:
Let the minimum votes required to qualify = Q and Total votes = T
Candidate A secured 30% of the total votes and did NOT qualify by 6 votes. ∴ 0.3T = Q - 6 ...(1)
Candidate B secured 40% of the total votes and got 6 votes more than the bare minimum to qualify ∴ 0.4T = Q + 6 ...(2)
(2) - (1), we get 0.1T = 12 ⇒ T = 120
Alternately, The difference between number of votes recieved by A and B is 12 which is 10% (40% - 30%) of total votes
∴ 10% of Total votes = 12
⇒ Total votes = 120
Hence, option (d).
» Your doubt will be displayed only after approval.