SSC CHSL 8th June Shift 3 - QA
If Priya and Renu can do a job in 12 hours (working together at their respective constant speeds) and Priya can do the job alone in 18 hours, in how many hours can Renu do the job alone?
- A.
36
- B.
24
- C.
27
- D.
21
Answer: Option A
Explanation :
Let Renu alone takes R hours to complete the task.
∴ = +
⇒ = -
⇒ R = 36 hours.
Hence, option (a).
Workspace:
The following table shows the sales of cars of four manufacturers for the period from 2015 to 2020 in a metropolitan city (all the figures are in thousands).
What are the total sales of cars of the four manufacturers under consideration in the city in the entire period of 6 years (from 2015 to 2020)?
- A.
1650000
- B.
1053000
- C.
1052000
- D.
1651000
Answer: Option B
Explanation :
Total sales of the car (in thousands) = 44 + 48 + 47 + 50 + 52 + 51 + 40 + 41 + 41 + 51 + 42 + 43 + 36 + 38 + 40 + 42 + 44 + 50 + 48 + 44 + 44 + 42 + 42 + 43 = 1053
∴ Total sales of the car = 1053000.
Hence, option (b).
Workspace:
If then the value of cosec (θ + 30°) is __________. [θ is an acute angle.]
- A.
- B.
- C.
- D.
Answer: Option B
Explanation :
sec2 θ = 3/4
⇒ cos2 θ = 4/3
⇒ cos θ = √3/2 [since θ is an acute angle we take positive value]
⇒ θ = 30°
Now, cosec(θ + 30)° = cosec 60° = 2/√3
Hence, option (b).
Workspace:
If + + 3x + q is exactly divisible by (x + 2) and (x - 2), then the values of p and q are:
- A.
p = q = 4
- B.
p = q = 4
- C.
p = q = -4
- D.
p = q = -4
Answer: Option D
Explanation :
If f(x) is divisible by x - a, then f(a) = 0
f(x) = px3 + x2 + 3x + q is divisible by x - 2, hence f(2) = 0
∴ 8p + 4 + 6 + q = 0
⇒ 8p + q = -10 ...(1)
f(x) = px3 + x2 + 3x + q is divisible by x + 2, hence f(-2) = 0
∴ -8p + 4 - 6 + q = 0
⇒ -8p + q = 2 ...(2)
Solving (1) and (2), we get
q = -4 and p = -3/4
Hence, option (d).
Workspace:
The following pie chart is the distribution of 36 marbles among three persons. The number of marbles that Madhuri has is ________.
- A.
18
- B.
20
- C.
16
- D.
12
Answer: Option A
Explanation :
Number of marbles with Madhuri = 180/360 × 36 = 18.
Hence, option (a).
Workspace:
Study the given table and answer the question that follows.
Given that the total number of students is 100.
If at least 60% marks in B and C are required for pursuing Post-doc in B, how many students in total will be eligible to pursue higher studies in B and C?
- A.
38
- B.
36
- C.
46
- D.
48
Answer: Option C
Explanation :
Number of students getting 60% or more marks in B = 20
Number of students getting 60% or more marks in C = 26
Totla number of students getting 60% or more marks in B and C = 20 + 26 = 46
Hence, option (c).
Workspace:
The surface area of a cube is 726 cm2. Find the volume of the cube
- A.
2744 cm3
- B.
1729 cm3
- C.
1331 cm3
- D.
2197 cm3
Answer: Option C
Explanation :
Surface area of a cube of side 'a' = 6a2 = 726
⇒ a2 = 121
⇒ a = 11
Volume of the cube = a3 = 113 = 1331 cm3
Hence, option (c).
Workspace:
If a number 7P323Q is completely divisible by 88, then the values of P and Q, respectively, are:
- A.
3; 2
- B.
2; 3
- C.
4; 2
- D.
9; 2
Answer: Option Q
Explanation :
Since 7P323Q is divisible by 88, it will be divisible by 8 as well as 11.
For 7P323Q to be divisible by 8, 23Q should be divisible by 8.
Hence, Q has be 2
Now, the number is 7P3232,
u = 2 + 2 + P = 4 + P
t = 3 + 3 + 7 = 13
∴ u - t = 4 + P - 13 = P - 9
⇒ P = 9
Hence, option (d).
Workspace:
If a : b = 2 : 5 and b : c = 3 : 4, find the value of a : b : c.
- A.
6 : 16 : 21
- B.
2 : 5 : 7
- C.
6 : 15 : 20
- D.
3 : 8 : 10
Answer: Option C
Explanation :
a : b = 2 : 5 = 6 : 15
b : c = 3 : 4 = 15 : 20
∴ a : b : c = 6 : 15 : 20
Hence, option (c).
Workspace:
Find the length of diagonal of a cuboid 13 m long, 7 m broad and 3 m high.
- A.
m
- B.
m
- C.
m
- D.
m
Answer: Option D
Explanation :
Length of body diagonal =
=
=
Hence, option (d).
Workspace:
If half of the quantity of sugar in a bag was sold at a profit of 20%, a quarter of the quantity of sugar in the bag was sold at a profit of 16%, and the remaining sugar in the bag was sold at a profit of 24%, and the total profit obtained by selling all the sugar in the bag was ₹90, what was the cost price of the entire quantity of sugar in the bag?
- A.
₹450
- B.
₹750
- C.
₹500
- D.
₹400
Answer: Option A
Explanation :
Let the total quantity of the sugar in bag = 100 kg while cost price of sugar is Rs. x/kg.
50 kg is sold at 20% profit, hence profit = 50 × 0.2x = 10x
25 kg is sold at 16% profit, hence profit = 25 × 0.16x = 4x
25 kg is sold at 24% profit, hence profit = 25 × 0.24x = 6x
∴ Total profit = 10x + 4x + 6x = 20x
Now, 20x = 90
⇒ x = 4.5
∴ Total cost price of the bag of sugar = 100x = Rs. 450
Hence, option (a).
Workspace:
If two circles of radii 28 cm and 18 cm touch each other externally, then the length of a common tangent is _________. [Give your answer correct to 2 decimal places.]
- A.
40.90 cm
- B.
42.00 cm
- C.
44.90 cm
- D.
44.12 cm
Answer: Option C
Explanation :
Length of Direct Common Tangent =
∴ = = 44.90
Hence, option (c).
Workspace:
How much water (in ml) should be added to 300 ml of a 75% milk and water mixture so that it becomes a 45% milk and water mixture?
- A.
300
- B.
250
- C.
150
- D.
200
Answer: Option D
Explanation :
Amount of milk initially = 300 × 75%
Let x liters of water is added.
Amount of milk finallly = (300 + x) × 45%
Amount of milk finallly = Amount of milk initially
∴ (300 + x) × 45% = 300 × 75%
⇒ 45x = 300 × 30
⇒ x = 200 liters
Hence, option (d).
Workspace:
The marked price of a shirt is ₹1,200. The shopkeeper gives successive discounts of 25% and 20%. Find the selling price of the shirt.
- A.
₹660
- B.
₹640
- C.
₹720
- D.
₹680
Answer: Option C
Explanation :
Price after 25% discount = 3/4 × 1200
Price after another 20% discount = 4/5 × 3/4 × 1200 = Rs. 720
Hence, option (c).
Workspace:
A batch of 30 students took an intelligence test in an institution. 20 of them scored an average of 75 marks and the remaining students scored an average of 87 marks. What is the average score of the entire batch of students?
- A.
79
- B.
75
- C.
78
- D.
77
Answer: Option A
Explanation :
Total marks of all 30 students = 20 × 75 + 10 × 87 = 2370
Average marks of all 30 students = 2370/30 = 79.
Hence, option (a).
Workspace:
Find the value of p from the following.
1 ÷ ÷ = 1 × ÷
- A.
12
- B.
18
- C.
20
- D.
6
Answer: Option A
Explanation :
1 ÷ ÷ = 1 × ÷
⇒ ÷ = × 4
⇒ = 5
⇒ p = 12
Hence, option (a).
Workspace:
Sundar lends a sum of ₹6,000 to Mahesh at an interest rate of 10% p.a., compounded annually. What will be the amount at the end of 2 years?
- A.
₹7,160
- B.
₹7,250
- C.
₹7,200
- D.
₹7,260
Answer: Option D
Explanation :
Amount after two years = 6000 × 1.12 = 6000 × 1.21 = Rs. 7260
Hence, option (d).
Workspace:
At 19% discount, the selling price of a book is ₹453.60. What is its marked price (in ₹)?
- A.
690
- B.
490
- C.
520
- D.
560
Answer: Option D
Explanation :
Selling price = Marked price × (1 - 19%)
⇒ 453.60 = MP × 0.81
⇒ MP = 453.60/0.81 = 560
Hence, option (d).
Workspace:
Kumar’s salary is ₹ 30,000 per month. He spends 25% of this on food and rent and 20% of the remaining on education. But he pays 5% of his total salary on paying the income tax and saves ₹ 8,000 after all these three deductions. What is the amount (in ₹.) available with him after his savings?
- A.
8500
- B.
7500
- C.
7250
- D.
8550
Answer: Option A
Explanation :
Amount spend on Food = 25% of 30,000 = 7,500
Amount remaining = Rs. 22,500
Amount spent on education = 20% of 22,500 = Rs. 4,500
Amount spent on income tax = 5% of 30,000 = Rs. 1,500
Savings = Rs. 8,000
Amount left after all deductions = 30,000 - 7,500 - 4,500 - 1,500 - 8,000 = Rs. 8,500
Workspace:
If x3 + y3 = 416 and x + y = 8, then find x4 + y4.
- A.
3002
- B.
3204
- C.
3004
- D.
3104
Answer: Option D
Explanation :
We know, (x + y)3 = x3 + y3 + 3xy(x + y)
⇒ 83 = 416 + 3 × xy × 8
⇒ 512 - 416 = 24xy
⇒ xy = 96/24 = 4
Now, x2 + y2 = (x + y)2 - 2xy = 64 - 8 = 56
Squaring both sides we get,
(x2 + y2)2 = 562
⇒ x4 + y4 + 2x2y2 = 3136
⇒ x4 + y4 + 32 = 3136
⇒ x4 + y4 = 3104
Hence, option (d).
Workspace:
Simplify the following expression.
323 - 3(322) (12) + 3(32) (123) - 123
- A.
8000
- B.
4000
- C.
16000
- D.
800
Answer: Option A
Explanation :
We know, (x - y)3 = x3 - 3x2y + 3xy2 - y3
∴ 323 - 3(322) (12) + 3(32) (123) - 123 = (32 - 12)3 = 203 = 8000
Hence, optin (a).
Workspace:
A ship sails out to a mark at the speed of 15 km/h and sails back to the starting point at the speed of 10 km/h. The average speed of sailing of the ship is:
- A.
12 km/h
- B.
15 km/h
- C.
13 km/h
- D.
14 km/h
Answer: Option A
Explanation :
Let the distance between starting point and the mark be 150 kms.
Time taken to go to the mark = 150/15 = 10 hours
Time taken to come back = 150/10 = 15 hours
∴ Average speed = (150 + 150)/(10 + 15) = 300/25 = 12 kmph
Hence,, option (a).
Workspace:
A woman spends 25% of her income. If her expenditure is ₹1,250, then find her income.
- A.
₹2,500
- B.
₹5,000
- C.
₹1,250
- D.
₹1,000
Answer: Option B
Explanation :
Expenditure = 25% of Income = Rs. 1,250
⇒ 1/4 × Income = 1250
∴ Income 1250 × 4 = Rs. 5000
Hence, option (b).
Workspace:
Three cities, A, B, and C are located such that they form the vertices of an equilateral triangle if joined by straight lines. Rashid travels from A to B at the speed of 40 km/h, from B to C at the speed of 60 km/h and from C to A at the speed of 72 k /h. Find the average speed of Rashid for the entire journey.
- A.
54 km/h
- B.
56
- C.
55 km/h
- D.
57
Answer: Option A
Explanation :
Let the sides of the equilaterl triangle be 360 kms each.
Time taken to travel from A to B = 360/40 = 9 hours
Time taken to travel from B to C = 360/60 = 6 hours
Time taken to travel from C to A = 360/72 = 5 hours
∴ Total time taken = 9 + 6 + 5 = 20 hours to travel a total of 360 + 360 + 360 = 1080 kms.
∴ Average speed = 1080/20 = 54 kmph.
Hence option (a).
Workspace:
The perimeter of an equilateral triangle is 75 cm. Find its area.
- A.
cm²
- B.
cm²
- C.
cm²
- D.
cm²
Answer: Option B
Explanation :
Perimeter = 3 × Side = 75 cm.
∴ Side = 25 cm.
Area of an equlateral triangle = (side)2
=
=
Hence, option (b).
Workspace: