If x3 + y3 = 416 and x + y = 8, then find x4 + y4.
Explanation:
We know, (x + y)3 = x3 + y3 + 3xy(x + y) ⇒ 83 = 416 + 3 × xy × 8 ⇒ 512 - 416 = 24xy ⇒ xy = 96/24 = 4
Now, x2 + y2 = (x + y)2 - 2xy = 64 - 8 = 56
Squaring both sides we get,
(x2 + y2)2 = 562 ⇒ x4 + y4 + 2x2y2 = 3136 ⇒ x4 + y4 + 32 = 3136 ⇒ x4 + y4 = 3104
Hence, option (d).
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