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Explanation:

Given, x = 3y   ...(1)

Also, x + y = 20   ...(2)

Substituting y = 3x from (1) in (2)

⇒ 3y + x = 20
⇒ 4y = 20
⇒ y = 5

∴ x = 3y = 15

Hence, option (c).

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