Discussion

If $\frac{5 cot \theta +\sqrt{3} \cos ec \theta }{2\sqrt{3} \cos ec \theta +3 cot \theta }$ = 1, 0° < θ < 90° then the value of $\frac{{\displaystyle \frac{7}{2}}{\cot }^2\mathrm{\theta }-{\displaystyle \frac{3}{4}}{\mathrm{cosec}}^2\mathrm{\theta }}{4{\sin }^2\mathrm{\theta }+{\displaystyle \frac{3}{2}}{\tan }^2\mathrm{\theta }}$ will be: