Discussion

Explanation:

2 cos² θ - 5 cos θ + 2 = 0

2 cos² θ - 4 cos θ - cos θ + 2 = 0

2 cos θ (cos θ - 2) - 1 (cos θ - 2) = 0

(cos θ - 2) (2 cos θ - 1) = 0

cos θ = 2 or cos θ = $\frac{1}{2}$

cos θ = 2 is not possible.

So, cos θ = $\frac{1}{2}$

sec θ = 2

tan θ = $\sqrt{se{c}^2\theta -1}$ = $\sqrt{4-1}$ = $\sqrt{3}$

∴ (sec θ + tan θ) = 2 + $\sqrt{3}$

Hence, the correct answer is Option A

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