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Explanation:

Let the two numbers be hx and hy, where h is the HCF of thest two numbers and LCM of these numbers = hxy.

Now, (hx + hy)2 - (hx - hy)2
= (hx)2 + (hy)2 + 2h2xy - ((hx)2 + (hy)2 - 2h2xy)
= 4h2xy
= 4 × h × hxy
= 4 × HCF × LCM

Hence, option (a).

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