Please submit your concern

Explanation:

The sum of the first 15 terms in an arithmetic progression is 200 , while the sum of the next 15 terms is 350 . Then the common difference is

Sum of n terms of an AP = n/2 × [2a + (n - 1)d]

Sum of first 15 terms = 200
∴ 200 = 15/2 × (2a + 14d)
⇒ 2a + 14d = 80/3   ...(1)

Sum of first 30 terms = 200 + 350 = 550
∴ 550 = 30/2 × (2a + 29d)
⇒ 2a + 29d = 110/3   ...(2)

(2) - (1), we get
15d = 30/3
⇒ d = 10/15 = 2/3

Hence, option (b).

Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All