Please submit your concern

Explanation:

For a number to be divisible by 6, the sum of its digits should be divisible by 3 and it's units digit should be even.

Since, abcde is divisible by 6,
a + b + c + d + e = multiple of 3, and
e is an even number

Option (a): edcba
Here the units digit is a which is not necessarily even, hence edcba is not definitely divisible by 6.

Option (b): eee
Here units digit e is even and sum of the digits = 3e which is a multiple of 3, hence eee is definitely divisible by 6.

Option (c): bbadcacede
Here units digit ​​​​​​​e is even and sum of the digits = 2(a + b + c + d + e) which is a multiple of 3, hence eee is definitely divisible by 6.

Option (d): cdbae
Here units digit ​​​​​​​e is even and sum of the digits = (a + b + c + d + e) which is a multiple of 3, hence eee is definitely divisible by 6.

Hence, option (a).