The set of all possible values of f(x) for which (81)x + (81)f(x) = 3 is
Explanation:
(81)x + (81)f(x) = 3
⇒ (3)4x + (3)4f(x) = 3
⇒ (3)4x-1 + (3)4f(x)-1 = 1 ...(1)
Now, power of a positive number is always greater than 0.
∴ (3)4x-1 > 0 and (3)4f(x)-1 > 0
From (1): Sum of two positive numbers is 1. This is only possible when both number are less than 1.
⇒ (3)4f(x)-1 < 1
⇒ 4f(x) - 1 < 0
⇒ f(x) < 1/4 or 0.25
∴ f(x) ∈ (-∞, 0.25)
Hence, option (c).
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