Discussion

Explanation:

Let the lengths of trains A and B be ‘A’ and ‘B’ and their speeds be ‘a’ and ‘b’ respectively.

Time taken for front end of A to cross rear end of B = 46 seconds

⇒ 46 = Ba+b

⇒ B = 46a + 46b   …(1)

Total time taken for rear ends of the two train to cross each other = (46 + 69) = 115 seconds

⇒ 115 = A+Ba+b

⇒ A + B = 115a + 115b   …(2)

(2) - (1)

⇒ A = 69a + 69b   …(3)

Now, AB = 69(a+b)46(a+b) = 6946 = 32

Hence, option (b). 

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