The area enclosed by 2|x| + 3|y| ≤ 6 is ____________ sq. units.
Explanation:
Consider, 2|x| + 3|y| = 6
Case 1: x > 0 and y > 0 [Quandrant I] ⇒ 2x + 3y = 6
Case 2: x < 0 and y > 0 [Quandrant II] ⇒ - 2x + 3y = 6
Case 3: x < 0 and y < 0 [Quandrant III] ⇒ - 2x - 3y = 6
Case 4: x > 0 and y < 0 [Quandrant IV] ⇒ 2x - 3y = 6
Each of these 4 lines can be drawn in their respective quadrants as shown in the figure.
We need the area of region bounded by these 4 lines.
Area of region I = 1/2 × 3 × 2 = 3 sq. units
Similarly area of region II, III and IV = 3 sq. units each.
∴ Area of all the 4 regions combined = 3 + 3 + 3 + 3 = 12 sq. units
Hence, 12..
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