A, B and C can complete a piece of work in 10, 20 and 40 days respectively. They work on a rotation basis with A working on the first day, B on the second. C the third. Then again A on the fourth day and so on. In how many days the work gets completed?
Explanation:
Let the total units of work be LCM (10, 20, 40) = 40.
A completes 40/10 = 4 units per day; Similarly, B and C will complete 2 and 1 units respectively.
So, at the end of one cycle (first 3 days) they will have completed 4 + 2 + 1 = 7 units of work.
They can carry out [40/7] = 5 such cycles thereby completing 35 units of work.
The next day A completes 4 units of work leaving 1 unit of work.
The next day, B will complete the work in ½ part of the day.
Total time = 5 × 3 + 1 + ½ = 16.5 days.
Hence, 16.5.
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