The total number of positive integer solutions of 21 < a + b + c < 25 is
Explanation:
We know number of ways of distributing n identical objects among r different groups such that each groups gets at least one object is n-1Cr-1.
Now,
Case 1: a + b + c = 21. ∴ We need to distribute 21 among 3 different variables a, b & c. Number of ways of doing this = 21-1C3-1 = 20C2 = 190
Case 2: a + b + c = 22. Number of ways of doing this = 22-1C3-1 = 21C2 = 210
Case 3: a + b + c = 23. Number of ways of doing this = 23-1C3-1 = 22C2 = 231
Case 4: a + b + c = 24. Number of ways of doing this = 24-1C3-1 = 23C2 = 253
Case 5: a + b + c = 25. Number of ways of doing this = 25-1C3-1 = 24C2 = 276
∴ Total number of ways = 190 + 210 + 231 + 253 + 276 = 1160
Hence, 1160.
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