There are two taps, T1 and T2, at the bottom of a water tank, either or both of which may be opened to empty the water tank, each at a constant rate. If T1 is opened keeping T2 closed, the water tank (initially full) becomes empty in half an hour. If both T1 and T2 are kept open, the water tank (initially full) becomes empty in 20 minutes. Then, the time (in minutes) it takes for the water tank (initially full) to become empty if T2 is opened while T1 is closed is
Explanation:
T1 alone can empty the tank in 30 minutes. T1 and T2 together can empty the tank in 20 minutes. Let the time taken by T2 alone is t minutes.
⇒ 130 + 1t = 120
⇒ t = 60 minutes.
Hence, 60.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.