If three consecutive coefficients in the expansion of (x + y)n are in the ratio 1 : 9 : 63, then the value of n is
Explanation:
We know (x + y)n = nC0 × xn + nC1 × xn-1 × y1 + nC2 × xn-2 × y2 + ... + nCn × yn
Let the three consecutive coefficients be nCr-1, nCr & nCr+1
Now, nCr-1 : nCr = 1 : 9 ⇒ n!(r-1)!×(n-r+1)! : n!(r)!×(n-r)! = 1 : 9
⇒ rn-r+1 = 19
⇒ 9r = n - r + 1
⇒ 10r = n + 1 ...(1)
Also, nCr : nCr+1 = 9 : 63 = 1 : 7 ⇒ n!(r)!×(n-r)! : n!(r+1)!×(n-r-1)! = 1 : 7
⇒ r+1n-r = 17
⇒ 7r + 7 = n - r
⇒ 8r = n - 7 ...(2)
Solving (1) & (2), we get
n = 39 & r = 4
Hence, 39.
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