Discussion

Explanation:

Here we need to break days till 31^st Oct 1984.

Complete years = 1983

Odd days in first 1600 years = 0
Odd days in next 300 years = 1
Odd days in next 83 years (20 leap and 63 non-leap years) = 20 × 2 + 63 × 1 = 103.

∴ Odd days in complete years = 0 + 1 + 103 = 104 odd days.

∴ Odd days in complete years = Remainder (104 ÷ 7) = 6 odd days.

Incomplete year (1984, a leap year)

Jan + Feb + Mar = 0 odd days,
Apr + May + Jun = 0 = odd days,
Jul + Aug + Sep = 1 odd day
Oct = 31

∴ Odd days in incomplete year = 0 + 0 + 1 + 31 = 32 odd days = 4 odd days.

∴ Total odd days till 31^st Oct 1984 = 6 + 4 = 10 odd days = 3 odd days.

∴ Day of the week on 31^st Oct 1984 will be 3 days after Sunday i.e., Wednesday.

Hence, option (d).

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