Discussion

Explanation:

We can draw the following figure from the given information.

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In ∆PQR,∠PRQ = 90° (tangent makes an angle of 90° with the radius.)

∴ ∆PQR is a right triangle with PQ as the hypotenuse

⇒ PQ2 = PR2 + QR2 

⇒ 102 = PR2 + 62 

⇒ PR2 = 100 - 36 = 64

⇒ PR = 8

Hence, 8.

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