In the following figure, lines AP, AQ and BC are tangent to the circle. The length of AP = 22. Find the perimeter of triangle ABC.
Explanation:
We know 2 tangents drawn from an external point to a circle are equal in length.
⇒ AP = AQ = 22
∴ If we consider point B as the external point, we have two tangents i.e., BP and BD.
⇒ BP = BD
Similarly, if we consider point C as the external point, we have two tangents i.e., CD and CQ.
⇒ CD = CQ
Now, Perimeter of ∆ABC = AB + BD + CD + AC
= AB + BP + CQ + AC
= AP + AQ
= 22 + 22 = 44
Hence, 44.
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