In the figure AB and CD are two diameters of the circle intersecting such that ∠COB = 50°. E is any point on arc CB. Find ∠CEB?
Explanation:
∠COB = ∠AOD = 50°
⇒ ∠CDB = 25° [Angle subtended by a chord on circle in same segment is half of the angle it subtends on the center.]
Now, angle subtended by a chord in opposite segments are complementary. If we consider the chord CB, then
⇒ ∠CDB + ∠CEB = 180°
⇒ ∠CEB = 180° - 25° = 155°
Hence, option (b).
» Your doubt will be displayed only after approval.