In the figure given below, AD : DE = 3 : 2 and BE : EC = 3 : 4. Find the ratio of area of triangle ADB to area of triangle CDE?
Explanation:
∆BDE and ∆CDE lie between same 2 parallel lines, hence the ratio of their areas is same as the ratio of their bases.
⇒ area(∆BDE)area(∆CDE) = 34 ...(1)
Similarly, area(∆ADB)area(∆BDE) = 32 ...(2)
(1) × (2)
⇒ area(∆ADB)area(∆CDE) = 98
Hence, option (b).
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