Discussion

Question:

A boatman can row 1 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current

Explanation:

Speed of the boatman upstream = $\frac{1}{\frac{20}{60}}$ = 3 km/hr.

Speed of the boatman downstream = $\frac{1}{\frac{18}{60}}$ = 10/3 km/hr.

Rate of current = $\frac{d o w n s t r e a m s p e e d - u p s t r e a m s p e e d}{2}$ = (10/3 - 3)/2 = 1/6 km/hr.

Hence, option (b).

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