Discussion

Explanation:

Let the work to be done = LCM (20, 30) = 60 units

∴ Efficiency of inlet tap = 60/20 = 3 units/hour
Efficiency of outlet tap = 60/30 = -2 units/hour [-ve indicates that the pipe is an outlet pipe]

Since the tap is located at one-fourth of the height from the bottom, it means that till one-fourth of the tank is filled only inlet pipe would be functioning. After that both inlet and outlet pipes would be functioning.

Time to fill one-fourth of the tank = 15/3 = 5 hours [only inlet pipe is functioning]

Time to fill remaining three-fourth of the tank = 45/(3 - 2) = 45 hours [both inlet and outlet pipes are functioning]

∴ Total time taken to fill the tank = 5 + 45 = 50 hours.

Hence, option (b).

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