During a severe draught, a society of 280 members had sufficient water stored for 180 days. After 100 days 40 new members joined the society. For how many days after the 40 new members joined the society would the rest of the water be sufficient assuming everyone consumed the same amount of water?
Explanation:
Total water available for 280 members for 180 days = 280 × 180 units
Total available consumed by 280 members in 100 days = 280 × 100 units
Water available after 100 days = 280(180 – 100) = 280 × 80 units
Number of members after 100 days = 320
∴ Number of days that the water will sufficient = 22400/320 = 70 days.
Hence, option (e).
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