Discussion

Question:

A can do a piece of work in 16 days. B is 60% more efficient than A. Find the number of days it takes B to do the same piece of work?

Explanation:

A’s 1 day’s work = $\frac{1}{16}$ ;

B is 60% more efficient than A, hence B can do 60% more work in a day than A can.

∴ B’s 1 day’s work = $\frac{1}{16} \times 1.6$ = $\frac{1}{10}$

∴ B can do the work in 10 days

Hence, option (a).

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