Average of 8 consecutive odd natural numbers is 36. Find the highest of these 8 numbers.
Explanation:
Let the first odd number be x.
∴ The numbers are: x, x + 2, x + 4, x + 6. x + 8, x + 10, x + 12 and x + 14.
Since these numbers are in Arithmetic Progression the average of these 8 numbers will be same as average of first and the last number.
∴ (x + x + 14)/2 = 36
⇒ 2x + 14 = 72
⇒ x = 29
∴ The highest number = x + 14 = 43.
Alternately, Since consecutive odd numbers will be in Arithmetic Progression and there avereage is 36 which will also be the average of 4th and 5th numbers.
∴ The 4th term will be 35 and 5th will be 37. Now, the 6th number will be 39, 7th will be 41 and 8th will be 43.
Hence, 43.
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