Discussion

Question:

The average of $32 \frac{1}{3}, 32 \frac{1}{4}, 31 \frac{2}{3}, 33 \frac{3}{4}$ is?

Explanation:

Sum of the numbers = $32 \frac{1}{3} + 32 \frac{1}{4} + 31 \frac{2}{3} + 33 \frac{3}{4}$

= 32 + 32 + 31 + 33 + $[\frac{1}{3} + \frac{1}{4} + \frac{2}{3} + \frac{3}{4}]$

= 128 + $[\frac{1}{4} + \frac{3}{4} + \frac{1}{3} + \frac{2}{3}]$

= 128 + 2 = 130.

Average = $\frac{130}{4}$ = $32 \frac{1}{2}$ .

Hence, option (a).

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