Discussion

Explanation:

Let the required number be x. 

Here divisors are 7, 9, 11 and remainders are 5, 7, 9.

The difference between respective divisors and remainders is 2.

∴ x = k × LCM (7, 9, 11) – 2 = 693k – 2.

x will be smallest when k = 1.

⇒ smallest value of x = 693 × 1 – 2 = 691.

Hence, option (b).

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