What is the smallest number which when divided by 7, 9, and 11 leaves remainders 5, 7, and 9 respectively?
Explanation:
Let the required number be x.
Here divisors are 7, 9, 11 and remainders are 5, 7, 9.
The difference between respective divisors and remainders is 2.
∴ x = k × LCM (7, 9, 11) – 2 = 693k – 2.
x will be smallest when k = 1.
⇒ smallest value of x = 693 × 1 – 2 = 691.
Hence, option (b).
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.