Product of two positive integers is 12615 and their HCF is 29. How many such pairs are possible?
Explanation:
Since HCF is 29
∴ Let numbers be 29a and 29b (where a and b are co-primes)
We have, 29a × 29b = 12615, or ab = 15.
Now, we have to write 15 as a product two co-prime numbers, hence
15 = 1 × 15 15 = 3 × 5
There are only two pairs of co-prime numbers whose product will be 15.
Hence, option (b).
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.