A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?
Explanation:
Suppose the original work would have been completed in d days.
Total work to be done = 30 × d
Work done in first 25 days = 30 × 25 Work done in next 12 days = 35 × 12
⇒ 30d = 30 × 25 + 35 × 12 ⇒ 30d = 750 + 420 ⇒ 30d = 1170 ⇒ d = 39
∴ Had 5 more men not been employed the work would have got delayed by (39 – 38 =) 1 day.
Hence, option (a).
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