O is the center of a circle of radius 10 cm. P is a point outside the circle and PQ is a tangent to the circle. What is the length (in cm) of PQ if the OP is 26 cm?
Explanation:
In right ∆OQP, OP2 = OQ2 + PQ2
⇒ 262 = 102 + PQ2
⇒ PQ2 = 676 – 100 = 576
⇒ PQ = 24
Hence, option (d).
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.