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Explanation:

0.027 = (0.3)³ 

⇒ $\frac{{\left(7.03\right)}^3-0.027}{{\left(7.03\right)}^2+2.109+{\left(0.3\right)}^2}$ = $\frac{{\left(7.03\right)}^3-{\left(0.3\right)}^3}{{\left(7.03\right)}^2+7.03\times 0.3+{\left(0.3\right)}^2}$

We know, a³ – b³ = (a - b)(a² – ab + b²)

⇒ $\frac{{\left(7.03\right)}^3-0.027}{{\left(7.03\right)}^2+2.109+{\left(0.3\right)}^2}$ = $\frac{(7.03-0.3)({\left(7.03\right)}^2+7.03\times 0.3+{\left(0.3\right)}^2)}{{\left(7.03\right)}^2+7.03\times 0.3+{\left(0.3\right)}^2}$ = 7.03 – 0.3 = 6.73

Hence, option (d).