The average of six numbers is m and the average of three of these is y. If the avearge of the reamining three is Z, then:
Explanation:
Sum of six numbers = 6 × m = 6m
Sum of first three numbers = 3 × y = 3y Sum of last three numbers = 3 × z = 3z
Sum of all 6 numbers = Sum of first 3 numbers + Sum of last 3 numbers ⇒ 6m = 3y + 3z ⇒ 2m = y + z
Hence, option (a).
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