In a simultaneous throw of a pair of dice, find the probability of getting a total more than 8?
Explanation:
Total number of outcomes = 6 × 6 = 36
Number of ways of getting a sum of 9: (6, 3), (3, 6), (5, 4), (4, 5) i.e., 4 ways Number of ways of getting a sum of 10: (6, 4), (4, 6), (5, 5) i.e., 3 ways Number of ways of getting a sum of 11: (6, 5), (5, 6) i.e., 2 ways Number of ways of getting a sum of 12: (6, 6) i.e., 1 way
Total number of ways of getting sum more than 8 = 4 + 3 + 2 + 1 = 10 ways
∴ Required probaility = 10/36 = 5/18
Hence, option (c).
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