Discussion

Question:

If A = 30°, what is the value of: $\frac{8 s i n A + 11 c o s e c A - \cot^{2} A}{10 c o s 2 A}$

Explanation:

Given, $\frac{8 \sin 30 ° ° + 11 c o s e c 30 ° - \cot^{2} 30 °}{10 \cos 60 °}$

= $\frac{8 \times \frac{1}{2} + 11 \times 2 - {(\sqrt{3})}^{2}}{10 \times \frac{1}{2}}$ = $\frac{4 + 22 - 3}{5}$ = $\frac{23}{5}$ = $4 \frac{3}{5}$

Hence, option (b).

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