Find the sum of the greatest and the smallest number which may replace k in the number 3281k6 to make the number divisible by 6.
Explanation:
To make 3281k6 divisible by 6, the number should be divisible by both 2 and 3.
Since, one’s digit of the number is even, the number is divisible by 2 for any value of k.
Now, to make the number also divisible by 3 ⇒ 3 + 2 +8 + 1 +k + 6 = 20 + k should be divisible by 3.
∴ Smallest value of k = 1 while the greatest value = 7.
⇒ Required sum = 1 + 7 = 8
Hence, option (b).
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